無法在某些Windows XP/Server 2003計算機上建立HTTPS連接

Question

我們在運行Windows XP和Windows Server 2003的某些計算機上的應用程序出現問題。嘗試通過HTTPS連接到我們的web服務時，應用程序崩潰。事件查看器在崩潰後顯示以下內容：

Exception Info: System.AccessViolationException 
Stack: 
    at System.Security.Cryptography.CAPISafe.CertGetCertificateChain(IntPtr, System.Security.Cryptography.SafeCertContextHandle, System.Runtime.InteropServices.ComTypes.FILETIME ByRef, System.Security.Cryptography.SafeCertStoreHandle, CERT_CHAIN_PARA ByRef, UInt32, IntPtr, System.Security.Cryptography.SafeCertChainHandle ByRef) 
    at System.Security.Cryptography.X509Certificates.X509Chain.BuildChain(IntPtr, System.Security.Cryptography.SafeCertContextHandle, System.Security.Cryptography.X509Certificates.X509Certificate2Collection, System.Security.Cryptography.OidCollection, System.Security.Cryptography.OidCollection, System.Security.Cryptography.X509Certificates.X509RevocationMode, System.Security.Cryptography.X509Certificates.X509RevocationFlag, System.DateTime, System.TimeSpan, System.Security.Cryptography.SafeCertChainHandle ByRef) 
    at System.Security.Cryptography.X509Certificates.X509Chain.Build(System.Security.Cryptography.X509Certificates.X509Certificate2) 
    at System.Net.Security.SecureChannel.VerifyRemoteCertificate(System.Net.Security.RemoteCertValidationCallback) 
    at System.Net.Security.SslState.CompleteHandshake() 
    at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(System.Net.Security.ProtocolToken, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartSendBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.ProcessReceivedBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReadFrame(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReceiveBlob(Byte[], System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(System.Net.Security.ProtocolToken, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartSendBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.ProcessReceivedBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReadFrame(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReceiveBlob(Byte[], System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(System.Net.Security.ProtocolToken, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartSendBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.ProcessReceivedBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReadFrame(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReceiveBlob(Byte[], System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(System.Net.Security.ProtocolToken, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartSendBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.ProcessReceivedBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReadFrame(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReceiveBlob(Byte[], System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(System.Net.Security.ProtocolToken, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartSendBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.ProcessReceivedBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReadFrame(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartReceiveBlob(Byte[], System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(System.Net.Security.ProtocolToken, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.StartSendBlob(Byte[], Int32, System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.ForceAuthentication(Boolean, Byte[], System.Net.AsyncProtocolRequest) 
    at System.Net.Security.SslState.ProcessAuthentication(System.Net.LazyAsyncResult) 
    at System.Net.TlsStream.CallProcessAuthentication(System.Object) 
    at System.Threading.ExecutionContext.runTryCode(System.Object) 
    at System.Runtime.CompilerServices.RuntimeHelpers.ExecuteCodeWithGuaranteedCleanup(TryCode, CleanupCode, System.Object) 
    at System.Threading.ExecutionContext.RunInternal(System.Threading.ExecutionContext, System.Threading.ContextCallback, System.Object) 
    at System.Threading.ExecutionContext.Run(System.Threading.ExecutionContext, System.Threading.ContextCallback, System.Object, Boolean) 
    at System.Threading.ExecutionContext.Run(System.Threading.ExecutionContext, System.Threading.ContextCallback, System.Object) 
    at System.Net.TlsStream.ProcessAuthentication(System.Net.LazyAsyncResult) 
    at System.Net.TlsStream.Write(Byte[], Int32, Int32) 
    at System.Net.PooledStream.Write(Byte[], Int32, Int32) 
    at System.Net.ConnectStream.WriteHeaders(Boolean) 
    at System.Net.HttpWebRequest.EndSubmitRequest() 
    at System.Net.HttpWebRequest.CheckDeferredCallDone(System.Net.ConnectStream) 
    at System.Net.HttpWebRequest.GetResponse() 
    at System.Web.Services.Protocols.WebClientProtocol.GetWebResponse(System.Net.WebRequest) 
    at System.Web.Services.Protocols.HttpWebClientProtocol.GetWebResponse(System.Net.WebRequest) 
    at System.Web.Services.Protocols.SoapHttpClientProtocol.Invoke(System.String, System.Object[]) 
    at {METHOD THAT CALLS WEBSERVICE} 

Web服務通信由服務引用處理。我們嘗試調用哪個Web服務並不重要。當我們使用完全不同的服務器時，甚至發生錯誤。

Answer 1

我們剛剛解決了這個問題。似乎只有在構建應用程序的計算機安裝了Visual Studio 2013時纔會出現此問題。

編輯：這是一個錯誤的假設。我們在我們的應用程序中使用libcef，這似乎是問題的根源。在沒有VS2013的機器上構建的版本包含錯誤版本的libcef。如果發生這種情況，應用程序將繼續沒有CEF功能，所以我們假設它正在工作。