Laravel 4模型

Question

我有一個簡單的（我想這很容易）的問題。我創建了一個名爲Player.php的新模型。它看起來像這樣：

<?php 

    class Player extends Eloquent { 


     protected $table = 'players'; 

     protected $fillable = array('char_name', 'sex'); 
     public $timestamps = false; 

} 

而且我已經在我的控制器中使用這樣的：

public function post_character() 
{ 
    $input = Input::all(); 

    $rules = array(
     'char_name' => 'required|unique:players,name|min:4', 
     'sex' => 'required' 
    ); 

    $validation = Validator::make($input, $rules); 

    if ($validation->fails()) { 
     return Redirect::to('create_character')->withErrors($validation); 
    } else { 

     $player = new Player; 
     $player->name = $input['char_name']; 
     $player->sex = $input['sex']; 
     $player->save; 

     return Redirect::to('managment')->with('success', 'Your character has been created.'); 
    } 
} 

這是我的形式：

@extends('base') 
@section('main') 

<div class="doc-content-box"> 
    <legend>Create a character</legend> 
    {{ Form::open(array('url' => 'create_character')) }} 

     <div class="control-group"> 
    {{ Form::label('char_name', 'Character name') }} 
    <div class="controls"> 
    {{ Form::text('char_name', null, array('placeholder' => 'Character name goes here..')) }} 
    </div> 
</div> 

    <div class="control-group"> 
     <div class="controls"> 
{{ Form::select('sex', array('1' => 'Male', '2' => 'Female'), '1'); }} 
</div> 
</div> 

<div class="form-actions"> 
    {{ Form::submit('Create a character', array('class' => 'btn btn-success')) }} 
    {{ Form::button('Help', array('class' => 'btn btn-default')) }} 
</div> 
    {{ Form::close() }} 
</div> 

@endsection 

而現在，這是我的錯誤：

SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`thefs`.`players`, CONSTRAINT `players_ibfk_1` FOREIGN KEY (`account_id`) REFERENCES `accounts` (`id`) ON DELETE CASCADE) (SQL: insert into `players` (`name`, `sex`) values (?, ?)) (Bindings: array (0 => 'Malx', 1 => '1',)) 

另外這裏是我的數據庫的屏幕截圖表「玩家」：

http://3.imgland.net/lL6EIv.png

Answer 1

好吧，錯誤說你在玩家桌上有一個限制。您在此創建用戶：

$player = new User; 
    $player->name = $input['char_name']; 
    $player->sex = $input['sex']; 
    $player->save; 

但是您沒有設置account_id。您可以通過默認的phpmyadmin把這個字段設置爲NULL或刪除外鍵約束或設置正確的ACCOUNT_ID

順便說一句，你可以寫：

$player = Player::create(array(
    'name' => ... 
)); 

而不是創建新的對象，然後將其保存

Answer 2

你似乎有你的模型，賬戶和球員之間的關係。你必須在你的控制器中建立這種關係。

Answer 3

這很可能是因爲您尚未在Eloquent模型中定義用戶和玩家之間的關係。這裏有一種常見的方法可以做到這一點（請注意，我正在用「用戶」替換您的「賬戶」模型[因此您的賬戶表將成爲用戶表，而玩家表將擁有user_id的外鍵而不是account_id] ，因爲它在Laravel的默認身份驗證機制中表現得更好）。

//user.php 
class User extends Eloquent { 
    //Define relation to players 
    public function players() { 
     return $this->hasMany('Player'); 
    } 
} 


//player.php 
class Player extends Eloquent { 
    //Your other player model code 

    //Define relation to user 
    public function user() { 
     return $this->belongsTo('User'); 
    } 
} 

現在創建一個新的播放器時：

$player = new Player(); 
$player->user_id = Auth::user()->id; 
$player->name = $input['char_name']; 
$player->sex = $input['sex']; 
$player->save(); 

這是假設用戶ID從任何用戶登錄來