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我在XSLT搞清楚這個分組的一個問題:分組在XSLT 2.0(通過短信分組)
的初始信息:
<Application>
<ApplicationItem LayoutPath="Attachments.Package.Attachment[bfd0b74d-2888-49d9-a986-df807f08ad8a].UniqueID" Value="bfd0b74d-2888-49d9-a986-df807f08ad8a" />
<ApplicationItem LayoutPath="Attachments.Package.Attachment[bfd0b74d-2888-49d9-a986-df807f08ad8a].Filename" Value="Document 1 Test" />
<ApplicationItem LayoutPath="Attachments.Package.Attachment[bfd0b74d-2888-49d9-a986-df807f08ad8a].URI" Value="https/.test.pdf" />
<ApplicationItem LayoutPath="Attachments.Package.Attachment[bfd0b74d-2888-49d9-a986-df807f08ad8b].UniqueID" Value="bfd0b74d-2888-49d9-a986-df807f08ad8b" />
<ApplicationItem LayoutPath="Attachments.Package.Attachment[bfd0b74d-2888-49d9-a986-df807f08ad8b].Filename" Value="Document 2 Test" />
<ApplicationItem LayoutPath="Attachments.Package.Attachment[bfd0b74d-2888-49d9-a986-df807f08ad8b].URI" Value="google.com" />
</Application>
預期的結果:
<Package>
<Attachment UniqueID="bfd0b74d-2888-49d9-a986-df807f08ad8a"
Filename="Document 1 Test"
URI="https/.test.pdf"/>
<Attachment UniqueID="bfd0b74d-2888-49d9-a986-df807f08ad8b"
Filename="Document 2 Test"
URI="google.com"/>
<Package>
我代碼: 我已經通過使用方括號中的ID完成了分組。
<xsl:for-each-group select="ApplicationItem[contains(@LayoutPath,'Attachments.Package.Attachment')]" group-by="substring-before(substring-after(@LayoutPath, 'Attachments.Package.Attachment['), ']')">
<Attachment>
<xsl:for-each select="current-group()">
<xsl:attribute name="UniqueID" select="current-grouping-key()"/>
<xsl:attribute name="Filename" select=".[contains(@LayoutPath,'Filename')]/@Value"/>
<xsl:attribute name="URI" select=".[contains(@LayoutPath,'URI')]/@Value"/>
</xsl:for-each>
<Attachment>
</xsl:for-each-group>
我的結果:
<Package>
<Attachment UniqueID="bfd0b74d-2888-49d9-a986-df807f08ad8a"
Filename=""
URI="https/.test.pdf"/>
<Attachment UniqueID="bfd0b74d-2888-49d9-a986-df807f08ad8b"
Filename=""
URI="google.com"/>
<Package>
我需要在代碼更改爲使用分組,因爲現在不工作只服用具有獨特的@LayoutPath最後ApplicationItem什麼。 我認爲問題與分組有關,但現在不要如何解決它。
謝謝你的作品。 – DanielCSD