2016-06-29 62 views
1
File schemaLocation = new File("/home/localpc/servletaddequi/src/main/resources/BackupSample/DEMO.xsd") 

如果我如上所述傳遞文件路徑,我能夠獲取文件。 但我想只從項目中傳遞文件的路徑,我怎麼能通過文件的路徑?如果我通過如下文件路徑:使用servlet在mule esb項目中獲取java變壓器中的文件路徑esb

File schemaLocation = new File("/foldername/filename.xsd"); 

它會產生誤差:

Failed to read schema document 'file:/BackupSample/DEMO.xsd', because 1) could not find the document; 2) the document could not be read; 3) the root element of the document is not <xsd:schema>. 
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:198) 
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.error(ErrorHandlerWrapper.java:134) 
    at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:437) 
    at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:347) 
    at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.reportSchemaErr(XSDHandler.java:4166) 
    at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.reportSchemaError(XSDHandler.java:4149) 
    at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.getSchemaDocument1(XSDHandler.java:2479) 
    at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.getSchemaDocument(XSDHandler.java:2187) 
    at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.parseSchema(XSDHandler.java:573) 
    at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadSchema(XMLSchemaLoader.java:617) 
    at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadGrammar(XMLSchemaLoader.java:575) 
    at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadGrammar(XMLSchemaLoader.java:541) 
    at com.sun.org.apache.xerces.internal.jaxp.validation.XMLSchemaFactory.newSchema(XMLSchemaFactory.java:252) 
    at javax.xml.validation.SchemaFactory.newSchema(SchemaFactory.java:627) 
    at javax.xml.validation.SchemaFactory.newSchema(SchemaFactory.java:643) 
    at com.test.Test.transformMessage(Test.java:38) 
    at org.mule.transformer.AbstractMessageTransformer.transform(AbstractMessageTransformer.java:141) 
    at org.mule.transformer.AbstractMessageTransformer.transform(AbstractMessageTransformer.java:89) 
    at org.mule.DefaultMuleMessage.transformMessage(DefaultMuleMessage.java:1602) 
    at org.mule.DefaultMuleMessage.applyAllTransformers(DefaultMuleMessage.java:1509) 

Caused by: java.io.FileNotFoundException: /BackupSample/DEMO.xsd (No such file or directory) 
    at java.io.FileInputStream.open(Native Method) 
    at java.io.FileInputStream.<init>(FileInputStream.java:146) 
    at java.io.FileInputStream.<init>(FileInputStream.java:101) 
    at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:90) 
    at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:188) 
    at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.setupCurrentEntity(XMLEntityManager.java:619) 
    at com.sun.org.apache.xerces.internal.impl.XMLVersionDetector.determineDocVersion(XMLVersionDetector.java:189) 
    at com.sun.org.apache.xerces.internal.impl.xs.opti.SchemaParsingConfig.parse(SchemaParsingConfig.java:582) 
    at com.sun.org.apache.xerces.internal.impl.xs.opti.SchemaParsingConfig.parse(SchemaParsingConfig.java:685) 
    at com.sun.org.apache.xerces.internal.impl.xs.opti.SchemaDOMParser.parse(SchemaDOMParser.java:530) 
    at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.getSchemaDocument(XSDHandler.java:2175) 
    ... 218 more 
+0

您可以添加您flow.xml。爲什麼你需要在Java轉換器中使用一個文件。我有點困惑,原因。 –

回答

0

請參閱從這個帖子答案:mule read single file from classpath during flow,你可以使用Thread.currentThread().getContextClassLoader().getResource("filename.xsd")獲得URL類。

因此你可以試試下面的代碼:

URL url = Thread.currentThread().getContextClassLoader().getResource("filename.xsd"); 
File schemaLocation = new File(url.getFile());