找到兼容套接字

Question

我有一個套接字ArrayList。我如何從列表中刪除我在變量中的同一個套接字。例如：

sockets = new ArrayList<Socket>(); 
sockets.add(socket); 
sockets.add(socket1); 
sockets.add(socket2); 

現在我想刪除它的索引，未知的socket1。

Answer 1

雖然你不能完全提供您的代碼，但在這裏，我給你舉個例子，如何刪除從下面的數組列表中的項目..

// create an empty array list with an initial capacity 
    ArrayList<String> arrlist = new ArrayList<String>(5); 

    // use add() method to add values in the list 
    arrlist.add("A"); 
    arrlist.add("B"); 
    arrlist.add("C"); 
    arrlist.add("D"); 
    arrlist.add("E"); 

    System.out.println("Size of list: " + arrlist.size()); 

    // let us print all the values available in list 
    for (String value : arrlist) { 
     System.out.println("Value = " + value); 
    } 

    // Removes first occurrence of "C" 
    arrlist.remove("C"); 

    System.out.println("Now, Size of list: " + arrlist.size()); 

    // let us print all the values available in list 
    for (String value : arrlist) { 
     System.out.println("Value = " + value); 
    } 

//又如

ArrayList<String> arlist=new ArrayList<String>(); 

//<E> it is return type of ArrayList 

arlist.add("First Element"); // adding element in ArrayList 
arlist.add("Second Element"); 
arlist.add("Third Element"); 
arlist.add("forth Element"); 
arlist.add("fifth Element"); 

// remove array list element by index number 
arlist.remove(3); 

// remove ArrayList element by Object value 
arlist.remove("fifth Element"); 

// get elements of ArrayList 
for(int i=0;i<arlist.size();i++) 
{ 
    System.out.println("ArrayList Element "+i+" :"+arlist.get(i)); 
} 

Answer 2

假設您有要刪除的Socket對象的引用，那麼只需撥打remove即可：ArrayList：

sockets.remove(socket1); 

這是有效的，因爲即使Socket未實現equals方法，也會使用Object類的引用相等性。只要該Socket對象在ArrayList中，remove就會將其刪除。

Answer 3

此代碼：

import java.io.IOException; 
import java.net.Socket; 
import java.util.ArrayList; 
import java.util.List; 

public class RemoveSocketFromAList { 
    public static void main(String[] args) throws IOException { 
     List<Socket> sockets = new ArrayList<>(3); 
     Socket google = new Socket("www.google.com", 80); 
     Socket bing = new Socket("www.bing.com" , 80); 
     Socket yahoo = new Socket("www.yahoo.com" , 80); 
     sockets.add(google); 
     sockets.add(bing ); 
     sockets.add(yahoo ); 
     System.out.println(sockets.size()); 
     sockets.remove(bing); 
     System.out.println(sockets.size()); 
     System.out.println(sockets); 
    } 
} 

輸出：

3 
2 
[Socket[addr=www.google.com/74.125.230.243,port=80,localport=62411], Socket[addr=www.yahoo.com/87.248.122.122,port=80,localport=62413]] 

List.remove()是有效的。