php如何插入逗號分隔json格式的多個字符串作爲一個值到mysql表？

Question

在PHP中，用下面的代碼：

$j_id = $jData[$j]['itop_id']; 
$res = '"name":"' . $jData[$j]['label'] . '","x":'. $jData[$j]['x'] . ',"y":' . $jData[$j]['y'] . ',"url":"' . $jData[$j]['icon_url'] . '"'; 

我能得到的值：

$j_id = 1; 
$res = "name":"AOL network","x":1032.5,"y":180,"url":"http://localhost/pathfind/web/env-production/itop-config-mgmt/images/business-process.png" 

當我嘗試插入的$ j_id價值觀和$資源到MySQL表用下面的代碼：

$sql = 'INSERT INTO coordinate_info (id,coordinate_res) VALUES ('.$j_id.','. $res.')'; 

我得到了錯誤：

Error: INSERT INTO coordinate_info (id,coordinate_res) VALUES (1,"name":"AOL network","x":1032.5,"y":180,"url":"http://localhost/pathfind/web/env-production/itop-config-mgmt/images/business-process.png") You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ':"AOL network","x":1032.5,"y":180,"url":"http://localhost/pathfind/web/env-produ' at line 1 

我想插入逗號分隔多個JSON格式的字符串到MySQL表中作爲一個列值。 你能給我一些建議嗎？ 在php中，如何將逗號分隔的值作爲一個值保存到mysql表中？

Answer 1

你應該真的使用準備好的語句和參數。如果安全不是一個問題，你可以改變你的SQL看起來像這樣：

$sql = 'INSERT INTO coordinate_info (id,coordinate_res) VALUES ('.$j_id.',"'. $res.'")';