tableViewCell中的UITapgestureRecogniser

Question

我有一個UILabel在UITableViewCell顯示電話號碼。當我點擊它時，我應該可以打電話給那個特定的號碼。所以爲了使它可點擊，我添加了一個UITapGestureRecognizer它。但我無法知道如何引用哪個點擊，我的意思是點擊哪個數字。

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    lblphone = [[UILabel alloc] initWithFrame:CGSizeMake(20,30,50,100)]; 
    lblphone.tag = 116; 
    lblphone.backgroundColor = [UIColor clearColor]; 
    lblphone.text=[NSString stringwithFormat:@"%@",phone]; 
    [lblphone setFont:[UIFont fontWithName:@"Helvetica" size:12]]; 
    [lblphone setLineBreakMode:UILineBreakModeWordWrap]; 
    [lblphone setUserInteractionEnabled:YES]; 

    UITapGestureRecognizer *tapGestureRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(labelButton:)]; 
    [tapGestureRecognizer setNumberOfTapsRequired:1]; 
    [lblphone addGestureRecognizer:tapGestureRecognizer]; 
    [tapGestureRecognizer release]; 
    [cell addSubview:lblphone]; 
} 

-(IBAction)labelButton:(UITapGestureRecognizer*)tapGestureRecognizer 
{ 
    NSIndexPath *indexPath; 
    UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:indexPath]; 
    UILabel *phoneno = (UILabel*)[cell viewWithTag:116]; 
    NSString *phoneNumber = [@"telprompt://" stringByAppendingString:phoneno.text]; 
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]]; 
} 

但是每當我看到最後一個單元格的PHONENUMBER在NSString *phoneNumber;

我該如何參考UITapGestureRecognizer中點擊哪個標籤？

Answer 1

使用lblphone.tag = indexPath.row + 1;而不是lblphone.tag = 116;在cellForRowAtIndexPath

您也可以不使用標籤實現這一目標。

下面

-(void)labelButton:(UITapGestureRecognizer*)tapGestureRecognizer 
{ 
    UILabel *phoneno = (UILabel *) tapGestureRecognizer.view; 
}