嘗試this鏈接以獲得接觸的細節,如PHONENUMBER,從電話簿名稱。 並檢查通過發佈喬恩
public List<Person> getContactList(){
ArrayList<Person> contactList = new ArrayList<Person>();
Uri contactUri = ContactsContract.Contacts.CONTENT_URI;
String[] PROJECTION = new String[] {
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.Contacts.HAS_PHONE_NUMBER,
};
String SELECTION = ContactsContract.Contacts.HAS_PHONE_NUMBER + "='1'";
Cursor contacts = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, PROJECTION, SELECTION, null, null);
if (contacts.getCount() > 0)
{
while(contacts.moveToNext()) {
Person aContact = new Person();
int idFieldColumnIndex = 0;
int nameFieldColumnIndex = 0;
int numberFieldColumnIndex = 0;
String contactId = contacts.getString(contacts.getColumnIndex(ContactsContract.Contacts._ID));
nameFieldColumnIndex = contacts.getColumnIndex(PhoneLookup.DISPLAY_NAME);
if (nameFieldColumnIndex > -1)
{
aContact.setName(contacts.getString(nameFieldColumnIndex));
}
PROJECTION = new String[] {Phone.NUMBER};
final Cursor phone = managedQuery(Phone.CONTENT_URI, PROJECTION, Data.CONTACT_ID + "=?", new String[]{String.valueOf(contactId)}, null);
if(phone.moveToFirst()) {
while(!phone.isAfterLast())
{
numberFieldColumnIndex = phone.getColumnIndex(Phone.NUMBER);
if (numberFieldColumnIndex > -1)
{
aContact.setPhoneNum(phone.getString(numberFieldColumnIndex));
phone.moveToNext();
TelephonyManager mTelephonyMgr;
mTelephonyMgr = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (!mTelephonyMgr.getLine1Number().contains(aContact.getPhoneNum()))
{
contactList.add(aContact);
}
}
}
}
phone.close();
}
contacts.close();
}
return contactList;
}
的答案,Person類
public class Person {
String myName = "";
String myNumber = "";
public String getName() {
return myName;
}
public void setName(String name) {
myName = name;
}
public String getPhoneNum() {
return myNumber;
}
public void setPhoneNum(String number) {
myNumber = number;
}
}
希望這可以幫助你。