在appium中刷卡後無法點擊元素

Question

我在亞馬遜購物應用上測試過。輕掃後找到一個元素，我有一個問題。 因爲列表視圖太長。我需要滾動（使用滑動API）。但是在滑動後，我無法再點擊該元素。它沒有返回任何錯誤，但應用程序沒有響應。

ScrollToElement（）函數將滑動到搜索元素。我試圖用觸摸動作輕拍，但沒有希望。我試圖挖掘一個確切的（372,466）的位置，它的工作原理，但它不是預期的。提前致謝。

public class FirstTest { 
    private AppiumDriver driver; 
    private Dimension size; 

    @BeforeClass 
    public void Setup() throws MalformedURLException { 


     String appActivityText = "com.amazon.mShop.home.HomeActivity"; 


     String appPackageText = "in.amazon.mShop.android.shopping"; 

     String fileLocation = "/system/app/"; 

     File classpathRoot = new File(System.getProperty("user.dir")); 
     File appDir = new File(classpathRoot, "\\STC"); 
     File app = new File(appDir, fileLocation); 
     System.out.println(app); 
     DesiredCapabilities capabilities = new DesiredCapabilities(); 

     capabilities.setCapability("device", "Android"); 
     capabilities.setCapability(CapabilityType.BROWSER_NAME, "Android"); 

     capabilities.setCapability(CapabilityType.PLATFORM, "Android"); 

     capabilities.setCapability(CapabilityType.VERSION, "4.4.2"); 

     capabilities.setCapability("deviceName", "420373d0de528100");//420373d0de528100 01a61316598f30e6 

     capabilities.setCapability("newCommandTimeout", "100"); 

     // capabilities.setCapability("app", "Chrome"/*app.getAbsolutePath()*/); 

     capabilities.setCapability("appPackage", appPackageText); 

     capabilities.setCapability("appActivity", appActivityText); 

     driver = new AndroidDriver(new URL("http://127.0.0.1:4723/wd/hub"), capabilities); 
     driver.manage().timeouts().implicitlyWait(80, TimeUnit.SECONDS); 

    } 

    @Test 
    public void Login() throws Exception { 
     // Click on Shop by Deparment link 
     driver.manage().timeouts().implicitlyWait(80, TimeUnit.SECONDS); 
     System.out.println("Click on Shop by Deparment link"); 
     driver.findElement(By.id("web_home_shop_by_department_label")).click(); 
     Thread.sleep(1000); 

     WebElement element = driver.findElement(By.name("Office Products Link")); 
     ScrollToElement(driver, element); 

     Thread.sleep(3000); 
//  TouchAction action = new TouchAction(driver); 
//  action.tap(372,466).perform(); 

     driver.findElement(By.name("Office Products Link")).click(); 

    } 
    @AfterClass 
    public void closeApp() { 
     // driver.closeApp(); 

    } 

public static void ScrollToElement(AppiumDriver driver, WebElement element){ 
     size = driver.manage().window().getSize(); 

     // Find swipe start and end point from screen's with and height. 
     // Find starty point which is at bottom side of screen. 
     int start = (int) (size.height * 0.20); 
     int starty = (int) (size.height * 0.80); 
     // Find endy point which is at top side of screen. 
     int endy = (int) (size.height * 0.20); 
     // Find horizontal point where you wants to swipe. It is in middle of 
     // screen width. 
     int startx = size.width/2; 

     while (true) { 
     driver.swipe(startx, starty, startx, endy, 3000); 
     start = start + (starty - endy); 
     if (element.getLocation().getY() - start < size.height - endy) { 
      break; 
     } 
     } 
    } 
} 

Answer 1

您的代碼存在的問題是您錯誤地使用了driver.findElement。 讓我解釋一下。 driver.findElement檢查屏幕上顯示的元素，如果發現，它會返回它。

您的代碼存在的問題是您在滾動功能之前做了driver.findElement，這意味着如果該元素當前不在屏幕上，測試將始終失敗。

這個代碼塊應該可以幫助您：

public WebElement findItemWithScrollingUsingBy(By by, int interactions) { 
    for (int i = 0; i < interactions; i++) { 
     if (driver.findElements(by).size() == 0) { 
      scrollDown(); 
     } else { 
      return driver.findElement(by); //you can add .click() here instead of returning the element 
     } 
    } 
    Assert.fail("Element not found"); 
    return null; 
} 

功能scrollDown()只是採取刷卡的代碼模塊和外部功能，這是乾淨多了。

要總結我的回答是：

1. 在屏幕上的元素搜索 - 如果發現，請單擊
2. 如果沒有找到 - 再拍滾動動作，並再次搜索該元素
3. 重複