如何序列化boost :: uuids :: uuid

Question

我目前在項目中使用boost :: uuids :: uuid，我想序列化包含boost :: uuids :: uuid的對象。我嘗試了下面的簡單示例，但出現錯誤：

/usr/include/boost/archive/basic_text_oprimitive.hpp:92：錯誤：'（操作符< <'in'（（boost :: archive： ：basic_text_oprimitive> *）this） - > boost :: archive :: basic_text_oprimitive> :: os < < t'

我真的很會說如果有人能幫助我。

#include <fstream> 
#include <boost/uuid/uuid.hpp> 
#include <boost/uuid/uuid_generators.hpp> 
#include <boost/uuid/uuid_serialize.hpp> 
#include <boost/archive/text_iarchive.hpp> 
#include <boost/archive/text_oarchive.hpp> 

class classA { 
public: 
    classA() : id(boost::uuids::random_generator()()) {} 
private: 
    friend class boost::serialization::access; 
    boost::uuids::uuid id; 
    template <class Archive> 
    void serialize(Archive& ar, const unsigned int version) { 
     ar & id; 
    } 
}; 

int main(void) { 
    classA a; 
    std::ofstream ofs("uuid.txt"); 
    boost::archive::text_oarchive oa(ofs); 
    oa << a; 
    ofs.close(); 
    return 0; 
} 

Answer 1

包含<boost/uuid/uuid_serialize.hpp>以啓用uuids的序列化。 http://www.boost.org/doc/libs/1_42_0/libs/uuid/uuid.html#boost/uuid/uuid_serialize.hpp