PHP的echo，簡單的foreach問題

Question

我有這樣的代碼呼應我從數據庫中的信息：

<?php 
    include('db_connect.php'); 
    mysql_query("SET NAMES UTF8"); 

$sql =" select * from hostess"; 
$query = mysql_query($sql); 


    while ($row = mysql_fetch_array($query)) { 
    echo "<div id='photo'>"; 
    echo "<div id='picture'>"; 
    echo "<td> <img src=foto/photo1/".$row['photo'] . "></td>"; 
    echo "</div>"; 
echo "<div id='rating'>"; 
    echo "</div>"; 
    echo "<div id='text'>"; 
    echo '<td><a href="hostess.php?id='.$row['id'].'">'. $row['first_name_en']."&nbsp;". $row['family_name_en']."</a></td>"; 
    echo "</div>"; 
    echo "</div>"; 
    } 
    ?> 

我也有我想把它取每個ID的評級系統。我的問題是，我如何爲每個id分配每個評分，我的意思是每個評分都必須有他自己的評分，他們不應該像現在一樣在一個div中顯示所有評分。我需要顯示每個人的評分div的結果。

我用所有結果的代碼是：

<?php 
// include update.php 
include_once 'update.php'; 
// get all data from tabel 
$arr_star = fetchStar(); 
?> 
<?php 
// start looping datas 
foreach($arr_star as $star){ ?> 
<h2>Star Rater - <?php echo $star['id'];?></h2> 
<ul class='star-rating' id="star-rating-<?php echo $star['id'];?>"> 
<?php /* getRating($id) is to generate current rating */?> 
    <li class="current-rating" id="current-rating-<?php echo $star['id'];?>" style="width:<?php echo getRating($star['id'])?>%"><!-- will show current rating --></li> 
    <?php 
    /* we need to generate 'id' for star rating.. this 'id' will identify which data to execute */ 
    /* we will pass it in ajax later */ 
    ?> 
    <span class="ratelinks" id="<?php echo $star['id'];?>"> 
    <li><a href="javascript:void(0)" title="1 star out of 5" class="one-star">1</a></li> 
    <li><a href="javascript:void(0)" title="1 star and a half out of 5" class="one-star-half">1.5</a></li> 
    <li><a href="javascript:void(0)" title="2 stars out of 5" class="two-stars">2</a></li> 
    <li><a href="javascript:void(0)" title="2 star and a half out of 5" class="two-star-half">2.5</a></li> 
    <li><a href="javascript:void(0)" title="3 stars out of 5" class="three-stars">3</a></li> 
    <li><a href="javascript:void(0)" title="3 star and a half out of 5" class="three-star-half">3.5</a></li> 
    <li><a href="javascript:void(0)" title="4 stars out of 5" class="four-stars">4</a></li> 
    <li><a href="javascript:void(0)" title="4 star and a half out of 5" class="four-star-half">4.5</a></li> 
    <li><a href="javascript:void(0)" title="5 stars out of 5" class="five-stars">5</a></li> 
    </span> 
</ul> 
<?php } ?> 

Answer 1

嘗試（有可能的錯別字，但希望你的想法）

switch ($star['id']) 
{ 
case 1: 
echo ' <li><a href="javascript:void(0)" title="1 star out of 5" class="one-star">1</a></li> 
    <li><a href="javascript:void(0)" title="1 star and a half out of 5" class="one-star-half">1.5</a></li>'; 
break; 
case 2: 
echo ' <li><a href="javascript:void(0)" title="2 stars out of 5" class="two-stars">2</a></li> 
    <li><a href="javascript:void(0)" title="2 star and a half out of 5" class="two-star-half">2.5</a></li> '] 
break; 
case 3: 
    echo ' <li><a href="javascript:void(0)" title="3 stars out of 5" class="three-stars">3</a></li> 
    <li><a href="javascript:void(0)" title="3 star and a half out of 5" class="three-star-half">3.5</a></li> '; 
    break; 
case 4: 
echo ' <li><a href="javascript:void(0)" title="4 stars out of 5" class="four-stars">4</a></li> 
    <li><a href="javascript:void(0)" title="4 star and a half out of 5" class="four-star-half">4.5</a></li> '; 
    break; 
case 5: 
    echo ' <li><a href="javascript:void(0)" title="5 stars out of 5" class="five-stars">5</a></li> '; 
break; 
default : 
    echo 'No vote'; 
    break; 
}