2013-01-11 56 views
2

飛鏢是偉大的,這就像編程。 IDE也很棒。 我遇到了在我看來是一個問題(對我來說)Dart JSON.parse函數。在我看來,問題是如果一個字符串 是一個整數,它會在Map中創建一個整數。這可能並不理想 ,因爲可能會出現字符串字段包含數字的情況。 例如。一個只包含街道號碼的地址。或者,也許我是 只是做錯了什麼。JSON.parse映射想要的字符串得到整數

的代碼暴露可能出現的問題的行是:

String sId  = mAcctData['I_Id']; 

我假定有此邏輯的解決方案,並且如果是這樣我會 欣賞被建議

httpSubmitAccountNrLoadEnd(HttpRequest httpReq) { 
    String sResponse = null; 
    if (httpReq.status != 200) { 
    print('On Http Submit Account Nr. There was an error : status =  ${httpReq.status}'); 
    } else { 
    print("On Return from Http Submit Account Nr. no error - status = ${httpReq.status}"); 
    sResponse = httpReq.responseText; 
    } 

    print("Response From Submit Account Nr. = ${sResponse}"); // print the received raw  JSON text 

    Map mAcctData = JSON.parse(sResponse); 
    print ("Json data parsed to map"); 

    print ("Map 'S_Custname' = ${mAcctData['S_Custname']}"); 
    String sCustName = mAcctData['S_Custname']; 

    print ("About to extract sId from Map data"); 
    String sId  = mAcctData['I_Id']; 
    print ("sId has been extracted from Map data"); 

    String sAcctNr = mAcctData['I_AcctNr']; 
    String sAcctBal = mAcctData['I_AcctBal']; 

的以下是控制檯輸出。 那就說明我有問題的行是:

Exception: type 'int' is not a subtype of type 'String' of 'sId'. 

 
About to send http message 
On Return from Http Submit Account Nr. no error - status = 200 
Response From Submit Account Nr. = {"S_Custname":"James Bond","I_Id":1,"I_Acctnr":123456789,"I_AcctBal":63727272,"I_AvailBal":0} 
Json data parsed to map 
Map 'S_Custname' = James Bond

About to extract sId from Map data

Exception: type 'int' is not a subtype of type 'String' of 'sId'.

Stack Trace: #0 httpSubmitAccountNrLoadEnd (http://127.0.0.1:3030/C:/Users/Brian/dart/transact01/transact01.dart:75:31)

1 submitAccountNr.submitAccountNr. (http://127.0.0.1:3030/C:/Users/Brian/dart/transact01/transact01.dart:33:59)

Exception: type 'int' is not a subtype of type 'String' of 'sId'. Stack Trace: #0 httpSubmitAccountNrLoadEnd (http://127.0.0.1:3030/C:/Users/Brian/dart/transact01/transact01.dart:75:31)

1 submitAccountNr.submitAccountNr. (http://127.0.0.1:3030/C:/Users/Brian/dart/transact01/transact01.dart:33:59)

問題:

  1. 有沒有解決辦法? (例如,強制JSON.parse創建字符串)
  2. 有沒有更好的方法來處理這個問題? (如:直接從JSON字符串中提取數據)

回答

0

只要打開你的整數轉換爲字符串,如果你想他們是這樣的:

{ 
    "S_Custname": "James Bond", 
    "I_Id": "1", 
    "I_Acctnr": "123456789", 
    "I_AcctBal": "63727272", 
    "I_AvailBal": "0" 
} 

現在應該正常工作。或者,使用.toString()將整數轉換爲字符串。

1

從我在你的sResponsemAcctData['I_Id']看到的是一個真正的int

{ 
    "S_Custname": "James Bond", 
    "I_Id": 1, 
    "I_Acctnr": 123456789, 
    "I_AcctBal": 63727272, 
    "I_AvailBal": 0 
} 

所以,如果你想獲得一個StringmAcctData['I_Id']您可以使用int.toString()

String sId = mAcctData['I_Id'].toString(); 
+0

好吧,是我不好。我以爲它是從它創建一個整數,因爲它是數字數據,而不是它是字符串表示中的數字字段。 –