2010-11-19 80 views
0

我正在嘗試向我的應用程序添加驗證。在允許將信息寫入數據庫之前,我有一些規則需要檢查。我已將基本數據驗證添加到模型中,但我還需要確保如果一個字段具有特定值,則需要此其他字段。有一次,NerdDinner教程asp.net報道了這個問題,我過去用它來驗證,但現在我找不到那個或其他的例子。這裏是我的模型:ASP.NET MVC2的自定義驗證規則應用程序

public class DayRequested 
{ 
    public int RequestId { set; get; } 
    [Required, DisplayName("Date of Leave")] 
    public string DateOfLeave { get; set; } 
    [Required, DisplayName("Time of Leave")] 
    public string TimeOfLeave { get; set; } 
    [Required, DisplayName("Hours Requested")] 
    [Range(0.5, 24, ErrorMessage = "Requested Hours must be within 1 day")] 
    public double HoursRequested { get; set; } 
    [Required, DisplayName("Request Type")] 
    public string RequestType { get; set; } 
    [DisplayName("Specify Relationship")] 
    public string Relationship { get; set; } 
    [DisplayName("Nature of Illness")] 
    public string NatureOfIllness { get; set; } 
    public bool AddedToTimesheet { get; set; } 

    public bool IsValid 
    { 
     get { return (GetRuleViolations().Count() == 0); } 
    } 

    public IEnumerable<RuleViolation> GetRuleViolations() 
    { 
     if (String.IsNullOrEmpty(DateOfLeave)) 
      yield return new RuleViolation("Date of Leave Required", "DateOfLeave"); 
     if (String.IsNullOrEmpty(TimeOfLeave)) 
      yield return new RuleViolation("Date of Leave Required", "TimeOfLeave"); 
     if ((HoursRequested < 0.5) || (HoursRequested > 24)) 
      yield return new RuleViolation("Hours must be in a period of one day", "HoursRequested"); 
     if (String.IsNullOrEmpty(RequestType)) 
      yield return new RuleViolation("Request Type is required", "RequestType"); 
     if ((!String.IsNullOrEmpty(NatureOfIllness)) && (NatureOfIllness.Length < 3)) 
      yield return new RuleViolation("Nature of Illness must be longer 2 characters", "NatureOfIllness"); 

     // Advanced data validation to make sure rules are followed 
     LeaveRequestRepository lrr = new LeaveRequestRepository(); 
     List<LeaveRequestType> lrt = lrr.GetAllLeaveRequestTypes(); 
     LeaveRequestType workingType = lrt.Find(b => b.Id == Convert.ToInt32(RequestType)); 

     if ((String.IsNullOrEmpty(Relationship)) && (workingType.HasRelationship)) 
      yield return new RuleViolation("Relationship is Required", "Relationship"); 
     if ((String.IsNullOrEmpty(NatureOfIllness)) && (workingType.HasNatureOfIllness)) 
      yield return new RuleViolation("Nature of Illness is Required", "NatureOfIllness"); 

     yield break; 
    } 
} 

我的控制器:

// 
    // POST: /LeaveRequest/Create 
    [Authorize, HttpPost] 
    public ActionResult Create(LeaveRequest leaveRequest, List<DayRequested> requestedDays) 
    { 
     if (ModelState.IsValid) 
     { 
      foreach (DayRequested requestedDay in requestedDays) 
      { 
       requestedDay.RequestId = leaveRequest.RequestId; 
       requestedDay.NatureOfIllness = (String.IsNullOrEmpty(requestedDay.NatureOfIllness) ? "" : requestedDay.NatureOfIllness); 
       requestedDay.Relationship = (String.IsNullOrEmpty(requestedDay.Relationship) ? "" : requestedDay.Relationship); 

       if (requestedDay.IsValid) 
        lrRepository.CreateNewLeaveRequestDate(requestedDay); 
       else 
        return View(new LeaveRequestViewModel(leaveRequest, requestedDays, lrRepository.GetLeaveRequestTypes())); 
      } 

      if (leaveRequest.IsValid) 
       lrRepository.CreateNewLeaveRequest(leaveRequest); 
      else 
       return View(new LeaveRequestViewModel(leaveRequest, requestedDays, lrRepository.GetLeaveRequestTypes())); 
     } 
     else 
      return View(new LeaveRequestViewModel(leaveRequest, requestedDays, lrRepository.GetLeaveRequestTypes())); 

     return RedirectToAction("Index", lrRepository.GetLeaveRequests(udh.employeeId)); 
    } 

ModelState.IsValid雖然IsValid代碼運行沒有設置爲false,並返回一個RuleViolation。所以我手動檢查IsValid它返回false。當我返回到視圖時,錯誤消息不會出現。我可能會錯過什麼?以下是一些意見摘錄。

Create.aspx

<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> 
    <h2>Create New Leave Request</h2> 
    <div><%= Html.ActionLink("Back to List", "Index") %></div> 
    <%= Html.Partial("RequestEditor", Model) %> 
    <div><%= Html.ActionLink("Back to List", "Index") %></div> 
</asp:Content> 

RequestEditor.ascx

<% using (Html.BeginForm()) {%> 
    <%= Html.ValidationSummary(true) %> 
     <table id="editorRows"> 
      <% foreach (var item in Model.DaysRequested) 
       Html.RenderPartial("RequestedDayRow", new EmployeePayroll.ViewModels.LeaveRequestRow(item, Model.LeaveRequestType)); %> 
     </table> 
     <p>Type your time to sign your request.</p> 
     <p><%= Html.LabelFor(model => model.LeaveRequest.EmployeeSignature) %>: 
      <%= Html.TextBoxFor(model => model.LeaveRequest.EmployeeSignature, new { Class="required" })%> 
      <%= Html.ValidationMessageFor(model => model.LeaveRequest.EmployeeSignature)%></p> 
     <p><input type="submit" value="Submit Request" /></p> 
<% } %> 

RequestedDayRow.ascx

<tbody class="editorRow"> 
    <tr class="row1"></tr> 
    <tr class="row2"> 
     <td colspan="2" class="relationship"> 
      <%= Html.LabelFor(model => model.DayRequested.Relationship)%>: 
      <%= Html.TextBoxFor(model => model.DayRequested.Relationship) %> 
      <%= Html.ValidationMessageFor(model => model.DayRequested.Relationship)%> 
     </td> 
     <td colspan="2" class="natureOfIllness"> 
      <%= Html.LabelFor(model => model.DayRequested.NatureOfIllness)%>: 
      <%= Html.TextBoxFor(model => model.DayRequested.NatureOfIllness) %> 
      <%= Html.ValidationMessageFor(model => model.DayRequested.NatureOfIllness)%> 
     </td> 
     <td></td> 
    </tr> 
</tbody> 

回答

1

它退出簡單 - 你只需要將你的驗證屬性應用到整個模型(或一個子類)。然後,驗證屬性獲取對模型的引用,而不是隻有一個屬性,並且可以對多個屬性執行檢查。

+0

是的,我張貼這之後回頭一看一次。 NerdDinner示例使用了一個名爲'ModelState.AddRuleViolations()'的輔助方法。哪些違規添加到'ModelState.AddModelError()'謝謝! – 2010-11-19 17:14:19