國家/城市/城鎮+計數列表

Question

我有三張表my_location1 & my_location2 & my_location3。 my_ is Prefix。位置1 =鄉村主義者。 location2 = statslist。 location3 =城鎮名單。在其他表中，我有用戶列表。現在我想列出在每個國家統計鎮（計數）中使用樹木樣式+水族用戶的所有位置（國家/地區 - 城鎮）。 （如何生成這個？）

DATABSE注：PID & PID1 =國家，PID2 =的ID統計的ID

my_location1：

id ++++++ name ++++++ active 

my_location2：

id ++++++ pid +++++++ name ++++++ active 

my_location3：

id ++++++ pid1 +++++++ pid2 ++++++ name ++++++ active 

my_user

id ++++++ name ++++++ location1 ++++++ location2 ++++++ location3 ++++++ active 

e.x

Country (print count Of users in this country) 
+++++++stats (print count Of users in this stats) 
++++++++++++town (print count Of users in this town) 
++++++++++++town (...) 
++++++++++++town (...) 
++++++++++++town (...) 
+++++++stats (...) 
++++++++++++town (...) 
+++++++stats (...) 
++++++++++++town (...) 
++++++++++++town (...) 
Country1 (...) 
+++++++stats (...) 
++++++++++++town (...) 
++++++++++++town (...) 
Country2 (...) 
+++++++stats (...) 
++++++++++++town (...) 
++++++++++++town (...) 
++++++++++++town (...) 
++++++++++++town (...) 
...more 

感謝您的幫助。

Answer 1

我沒有檢查的代碼，但它應該是這樣的：

function getCountries() 
{ 
    return mysql_query('SELECT c.*, (COUNT(*) from u WHERE u.location1 = c.id) AS user_count 
          from countrylist c 
          LEFT JOIN users u 
          ON u.location1 = c.id 
          WHERE c.active = 1' 
         ); 
} 

function getStats($countryId) 
{ 
    return mysql_query('SELECT s.*, (COUNT(*) from u WHERE s.location2 = s.id) AS user_count 
          from statslist s 
          LEFT JOIN users u 
          ON u.location2 = s.id 
          WHERE s.pid = ' . $countryId 
         ); 
} 

function getTowns($stateId) 
{ 
    return mysql_query('SELECT t.*, (COUNT(*) from u WHERE t.location3 = t.id) AS user_count 
          from townlist 
          LEFT JOIN users u 
          ON u.location3 = t.id 
          WHERE t.pid2 = ' . $stateId 
         ); 
} 

echo "<ul>\n"; 
while ($country = mysql_fetch_assoc(getCountries())) { 
    echo "<li>" . $country["name"] . "(" . $country["user_count"] . ")\n"; 
    echo "<ul>\n"; 

    while ($state = mysql_fetch_assoc(getStats($country["id"]))) { 
     echo "<li>" . $state["name"] . "(" . $state["user_count"] . ")\n<ul>\n"; 
     while ($town = mysql_fetch_assoc(getTowns($state["id"]))) { 
     echo "<li>" . $town["name"] . "(" . $town["user_count"] . ")</li>\n"; 
     } 
     echo "</ul>\n</li>\n"; 
    } 

    echo "<ul>\n</li>\n"; 
} 
echo "</ul>\n"; 

它可以而且應該進一步優化，但希望你的想法。另請注意，你的mysql結構是相當多餘的。