具有相同的名稱和兩個以上的數量

Question

我曾嘗試用下面的方法在我project.It做工精細挑選，從手機聯繫人挑接觸.....

• 但在某些情況下，我將無法正常工作...... 對於防爆：在與像個人/家庭的多個號碼相同名稱的情況下..

• 在這個階段，將只挑選第一number.so我無法挑選從接觸我。請給解決方案.....

代碼在這裏

public void onActivityResult(int reqCode, int resultCode, Intent data) { 
super.onActivityResult(reqCode, resultCode, data); 

switch (reqCode) { 
case (PICK_CONTACT) : 
    if (resultCode == Activity.RESULT_OK) { 

    Uri contactData = data.getData(); 
    Cursor c = managedQuery(contactData, null, null, null, null); 
    if (c.moveToFirst()) { 


     String id =c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts._ID)); 

     String hasPhone =c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); 

      if (hasPhone.equalsIgnoreCase("1")) { 
      Cursor phones = getContentResolver().query( 
         ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null, 
         ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id, 
         null, null); 
      phones.moveToFirst(); 
      cNumber = phones.getString(phones.getColumnIndex("data1")); 

      System.out.println("number is:"+cNumber); 
      } 
     /*name = c.getString(c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)); 

     Textcontact.setText(name);*/ 

     edt.setText(cNumber); 

    } 
    } 
    break; 
} 
} 

謝謝...

Answer 1

，而不是

phones.moveToFirst(); 

你可以瀏覽光標更item

int colIndex = phones.getColumnIndex("data1"); 
while (phones.moveToNext()) { 
    System.out.println("Found a number : " + phones.getString(colIndex)); 
}