如何讓套接字接受多個連接？

Question

目前我有一個只能接受一個連接的套接字服務器。任何第二個連接，它只是掛起，不做任何事情。

服務器可以從一個客戶端獲取消息發送。我現在只有服務器發回確認信息。

server.py：

import socket, sys 

# some vars 
HOST = "localhost"; 
PORT = 4242; 

# create the socket 
soc = socket.socket(socket.AF_INET, socket.SOCK_STREAM); 

# bind the socket to port 
server_addr = (HOST, PORT); 
print >>sys.stderr, "starting server %s on port %s" % (HOST, PORT); 
soc.bind(server_addr); 

# check for connections 
soc.listen(1); 

while True: 
    # wait for a connection 
    connection, client_address = soc.accept(); 
    try: 
     # since just test 
     # just send back whatever server receives 
     while True: 
      data = connection.recv(16); 
      if data: 
       connection.sendall(str(client_address[1]) + " said " + data); 
    finally: 
     connection.close(); 

client.py：

import socket, sys, thread 

# some vars 
HOST = "localhost"; 
PORT = 4242; 

# create the socket 
soc = socket.socket(socket.AF_INET, socket.SOCK_STREAM); 

# connect to server/port 
server_addr = (HOST, PORT); 
print >>sys.stderr, "connecting to %s on port %s" % (HOST, PORT); 
soc.connect(server_addr); 

# try to send data over 
while True: 
    try: 
     # send the message 
     msg = raw_input("Message: "); 
     soc.sendall(msg); 

     # check if there is response 
     amt_recd = 0; 
     amt_expd = len(msg); 

     while amt_recd < amt_expd: 
      data = soc.recv(16); 
      amt_recd += len(data); 
      print >>sys.stderr, data, "\n"; 
    finally: 
     msg = ''; 

Answer 1

有從服務器這個無限循環沒有退出條件：

while True: 
    data = connection.recv(16) 
    if data: 
     connection.sendall(str(client_address[1]) + " said " + data) 

如果客戶端關閉連接數據將是空的，但它仍然會繼續循環。修復：

while True: 
    data = connection.recv(16) 
    if not data: 
     break 
    connection.sendall(str(client_address[1]) + " said " + data) 

此外，即使修復此問題後，服務器一次只能處理一個連接。如果您希望一次爲多個客戶端提供服務，則需要使用select.select或爲每個客戶端連接分離線程。

另外，Python在語句結束時不需要分號。