1
我正面臨在android中的sqllite數據庫中創建多個表的問題。 這裏是我的代碼Android中的SQLite數據庫中的多個表?
public class DataHelper {
private static final String DATABASE_NAME = "example.db";
private static final int DATABASE_VERSION = 1;
private static final String TABLE_NAME = "table1";
private static final String SETTING_TABLE="setting";
private Context context;
private SQLiteDatabase db;
private SQLiteStatement insertStmt;
private static final String INSERT = "insert into " + TABLE_NAME +
"(name) values (?)";
private static final String INSERTSETTING = "insert into " + SETTING_TABLE +
"(name) values (?)";
public DataHelper(Context context) {
this.context = context;
OpenHelper openHelper = new OpenHelper(this.context);
this.db = openHelper.getWritableDatabase();
this.insertStmt = this.db.compileStatement(INSERT);
this.insertStmt = this.db.compileStatement(INSERTSETTING);
}
public SQLiteDatabase getDb() {
return this.db;
}
public long insert(String name) {
this.insertStmt.bindString(1, name);
return this.insertStmt.executeInsert();
}
private static class OpenHelper extends SQLiteOpenHelper {
OpenHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
db.execSQL("CREATE TABLE " + TABLE_NAME +
" (id INTEGER PRIMARY KEY, name TEXT)");
db.execSQL("CREATE TABLE " + SETTING_TABLE +
" (id INTEGER PRIMARY KEY, name TEXT)");
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion)
{
db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
onCreate(db);
}
}
}
你有什麼問題? It1s可以在SQLite上創建多個表。 – 2011-04-14 20:22:01
顯示您收到的錯誤.... – KevinDTimm 2011-04-14 20:22:47
當我想添加第二個表時,它在一個表內工作正常,而不是它給了我錯誤(表不存在)。 – Altaf 2011-04-14 20:25:11