2017-02-18 161 views
2

錯誤消息:休眠插入錯誤

javax.persistence.RollbackException:錯誤而犯下 交易

我無法保存用戶數據。這個錯誤已經出現,它遵循該項目的形式是:

方法保存:

public String addUser(Address a, User u) 
{ 
    u.setAddress(a); 
    userDAO.save(u); 
    return "User saved successfully!"; 
} 

的persistence.xml:

接收表單數據

public void save(User u) 
    { 
     EntityManager em = JPAUtil.getEntityManager(); 
     EntityTransaction tx = em.getTransaction();   

     try 
     { 
     tx.begin(); 
     if (u.getId_User()== null) { 

      em.persist(u); 
     } else { 
      em.merge(u); 
     } 
     tx.commit(); 
    } catch (Exception ex) { 
     ex.printStackTrace(); 
     if (tx != null && tx.isActive()) { 
      tx.rollback(); 
     } 
    } finally { 
     em.close(); 
    } 
} 

方法

<?xml version="1.0" encoding="UTF-8"?> 
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence"  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  xsi:schemaLocation="http://java.sun.com/xml/ns/persistence  http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"> 
<persistence-unit name="consultoriowebPU"> 
    <!-- Hibernate --> 
    <provider>org.hibernate.ejb.HibernatePersistence</provider> 
    <properties> 
     <property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/bd_consultorioweb?useUnicode=true&amp;characterEncoding=UTF-8&amp;characterSetResults=UTF-8"/> 
     <property name="javax.persistence.jdbc.user" value="root"/> 
     <property name="javax.persistence.jdbc.password" value=""/> 
     <property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver"/> 
     <property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect" /> 
     <property name="hibernate.hbm2ddl.auto" value="update"/> 
     <property name="hibernate.show_sql" value="true" /> 
     <property name="hibernate.format_sql" value="true" />    
    </properties> 
</persistence-unit> 

User.class [模型]:

@Entity 
public class User implements Serializable 
{ 
    private static final long serialVersionUID = 1L; 

    @Id @GeneratedValue 
    private Long Id_User; 
    private String email_User; 
    private String name_User; 
    private String password_User; 
    private int status_User; 
    @ManyToOne 
    private Address address; 
    //Get and set.. 
    } 

Address.class [模型]:

@Entity 
public class Address implements Serializable 
{ 
    private static final long serialVersionUID = 1L; 

    @Id @GeneratedValue 
    private Long Id_Address; 
    private String Country; 
    private String State; 
    private String City; 
    private String Neighborhood; 
    private String Street; 
    private Long Number; 
    private String Complement; 
    private String Zipcode; 

    //Get and set..  
} 

下面是使用的庫/罐的列表: http://imgur.com/a/NDmmQ 在控制檯中,僅插入SQL出現,然後錯誤消息和沒有數據記錄在數據庫中。

回答

1

我假設您正在填充用戶的地址實體是分離的實體。當用戶實體持久化/合併,那麼也地址實體將被持久化/合併

@ManyToOne(cascade = {CascadeType.PERSIST, CascadeType.MERGE}) 
@JoinColumn(name = "address_id") 
private Address address; 

現在:

我想補充以下級聯選項,用戶實體。

+0

它真的有效!但我不得不切換到:@JoinColumn(name =「address_id」)非常感謝! –

+1

太好了。很高興我可以幫助..是的,它應該當然是joincolumn ..一定是一直在回答 –