函數不在「if」語句中運行Python 3

Question

我試圖在Python中編寫一個逃生房間遊戲。
當我用pycharm運行代碼時，進程以「進程完成退出代碼0」結束。

定義函數有什麼不對嗎？
這裏是我的代碼（它是一個有點冗長）：

choice = None 

def main_choice(): 

    print("1. Examine door") 

    print("2. Examine painting") 

    print("3. Examine desk") 

    print("4. Examine bookshelf") 

    choice == input("Make your choice: ") 


def door(): 

    print("1. Try to open door") 

    print("2. Take a closer look") 

    print("3. Go back to where you were.") 

    door_choice = input("What now? ") 

    if door_choice == "1": 

     print("The door is too heavy to open with your bare hands.") 

     door() 

    if door_choice == "2": 

     print("There is a red light above the door, but it seems to have no purpose.") 

     print("You notice a 9 key keypad next to the door. It looks like it will accept a 3 digit code.") 

     keypad_code = input("Would you like to enter a code?").lower 

     if keypad_code == " yes": 

      guess = input("ENTER CODE: ") 

      if guess == complete_key: 

      print("The light turns green and you hear the sound of a mechanical lock unlocking. The door opens.") 

      print("YOU WIN!!!") 

     if guess != complete_key: 

      print("Wrong code.") 

      main_choice() 

    if door_choice == "3": 

     main_choice() 

    else: 

     print("You didn't answer") 


main_choice() 

if choice == "1": 

    print("You walk to the door") 

    door() 

我想，這可能是最後的「如果」的聲明，但我還不能肯定。

Answer 1

您需要更改choice == input("Make your choice: ")到choice = input("Make your choice: ")在main_choice功能：

def main_choice(): 

    print("1. Examine door") 

    print("2. Examine painting") 

    print("3. Examine desk") 

    print("4. Examine bookshelf") 

    choice = input("Make your choice: ") 

否則choice變量仍然是None和if choice == "1":將永遠是假的。

Answer 2

你應該寫：

choice = input("Make you choice: ") 

而不是：

choice == input("Make you choice: ") 

雙等號返回一個布爾值，而不是改變的值。