先進比例計算在TSQL

Question

我試圖在關係確定DD（branch）的比例爲AA，BB，CC其中DD存在於員工，客戶，水果的子集。每位員工的pcnt增加到1（100％）。

其分解，該計算必須滿足以下條件：

• 忽略子集（僱員，帳戶，水果），而不DD

| EMPLOYEE | ACCOUNT |  FRUIT | BRANCH | PCNT | 
--------------------------------------------------- 
|  123 | Fruit1 |  Apple |  AA | 0.1 |

• 忽略子集（僱員，帳戶，水果）被完全DD

| EMPLOYEE | ACCOUNT |  FRUIT | BRANCH | PCNT | 
--------------------------------------------------- 
|  123 | Fruit2 |  Apple |  DD | 0.05 |

• 按比例分配DD在AA，BB，子集內CC（員工，客戶，水果）

來源：

| EMPLOYEE | ACCOUNT |  FRUIT | BRANCH | PCNT | 
--------------------------------------------------- 
|  123 | Fruit1 | Strawberry |  AA | 0.05 | 
|  123 | Fruit1 | Strawberry |  BB | 0.02 | 
|  123 | Fruit1 | Strawberry |  CC | 0.07 | 
|  123 | Fruit1 | Strawberry |  DD | 0.10 |

分爲：

| EMPLOYEE | ACCOUNT |  FRUIT | BRANCH | PCNT | 
--------------------------------------------------- 
|  123 | Fruit1 | Strawberry |  AA | 0.09 | 
|  123 | Fruit1 | Strawberry |  BB | 0.03 | 
|  123 | Fruit1 | Strawberry |  CC | 0.12 |

的計算對於上述的子集比例將是：

AA + {AA * [DD/(AA + BB + CC)]} 

0.05 + {0.05 * [0.1/(0.05 + 0.02 + 0.07)]} = 0.09 
0.02 + {0.02 * [0.1/(0.05 + 0.02 + 0.07)]} = 0.03 
0.07 + {0.07 * [0.1/(0.05 + 0.02 + 0.07)]} = 0.12

• 這些計算和條件後，pcnt總和應爲1
• 可能存在的一些子集，其中不是所有的三（AA，BB，CC）是本

表結構

CREATE TABLE tbl (
    employee tinyint NOT NULL, 
    account varchar(10) NOT NULL, 
    fruit varchar(15) NOT NULL, 
    branch char(2) NOT NULL, 
    pcnt decimal(3,2) NULL 
    PRIMARY KEY (employee, account, fruit, branch))

樣本數據

INSERT INTO tbl (employee, account, fruit, branch, pcnt) VALUES 
(123, 'Fruit1', 'Apple', 'AA', '0.1'), 
(123, 'Fruit1', 'Mango', 'DD', '0.02'), 
(123, 'Fruit1', 'Mango', 'CC', '0.1'), 
(123, 'Fruit1', 'Mango', 'BB', '0.02'), 
(123, 'Fruit1', 'Mango', 'AA', '0.06'), 
(123, 'Fruit1', 'Pineapple', 'DD', '0.01'), 
(123, 'Fruit1', 'Pineapple', 'CC', '0.05'), 
(123, 'Fruit1', 'Pineapple', 'BB', '0.05'), 
(123, 'Fruit1', 'Pineapple', 'AA', '0.05'), 
(123, 'Fruit1', 'Strawberry', 'DD', '0.10'), 
(123, 'Fruit1', 'Strawberry', 'CC', '0.07'), 
(123, 'Fruit1', 'Strawberry', 'BB', '0.02'), 
(123, 'Fruit1', 'Strawberry', 'AA', '0.05'), 
(123, 'Fruit2', 'Apple', 'DD', '0.05'), 
(123, 'Fruit2', 'Mango', 'DD', '0.01'), 
(123, 'Fruit2', 'Mango', 'CC', '0.02'), 
(123, 'Fruit2', 'Mango', 'BB', '0.01'), 
(123, 'Fruit2', 'Mango', 'AA', '0.01'), 
(123, 'Fruit2', 'Pineapple', 'DD', '0.02'), 
(123, 'Fruit2', 'Pineapple', 'CC', '0.03'), 
(123, 'Fruit2', 'Pineapple', 'BB', '0.02'), 
(123, 'Fruit2', 'Pineapple', 'AA', '0.02'), 
(123, 'Fruit2', 'Strawberry', 'DD', '0.01'), 
(123, 'Fruit2', 'Strawberry', 'CC', '0.05'), 
(123, 'Fruit2', 'Strawberry', 'AA', '0.05')

我已經試過

SELECT b.*, 
    CASE WHEN (b.Sum_AA + b.Sum_BB + b.Sum_CC) > 0 THEN 'hello' 
    ELSE NULL 
    END 
FROM (
    SELECT a.*, 
     (SELECT SUM(pcnt) AS [pcnt] FROM dbo.tbl 
      WHERE employee = a.employee AND account = a.account AND fruit = a.fruit 
      AND branch = 'AA') AS [Sum_AA], 
     (SELECT SUM(pcnt) AS [pcnt] FROM dbo.tbl 
      WHERE employee = a.employee AND account = a.account AND fruit = a.fruit 
      AND branch = 'BB') AS [Sum_BB], 
     (SELECT SUM(pcnt) AS [pcnt] FROM dbo.tbl 
      WHERE employee = a.employee AND account = a.account AND fruit = a.fruit 
      AND branch = 'CC') AS [Sum_CC] 
    FROM (
     SELECT employee, account, fruit, SUM(pcnt) AS [Sum_DD] 
     FROM dbo.tbl 
     WHERE employee = 123 AND branch = 'DD' 
     GROUP BY employee, account, fruit) a) b 

截至上述查詢，我​​已經分組AA，BB，CC。但是，我不知道如何繼續。任何幫助表示讚賞。

Answer 1

不確定這是你需要的，試試這個。

WITH ct1 AS 
(  
    SELECT employee, account, fruit 
     ,SUM(CASE WHEN branch = 'AA' THEN pcnt ELSE 0 END) AS AA  
     ,SUM(CASE WHEN branch = 'BB' THEN pcnt ELSE 0 END) AS BB  
     ,SUM(CASE WHEN branch = 'CC' THEN pcnt ELSE 0 END) AS CC 
     ,SUM(CASE WHEN branch = 'DD' THEN pcnt ELSE 0 END) AS DD 
    FROM tbl 
    GROUP BY employee, account, fruit having SUM(CASE WHEN branch = 'DD' THEN 1 ELSE 0 END) >= 1  
) 
SELECT t.* 
    ,new_pcnt = t.pcnt + ROUND((t.pcnt * (DD /(AA + BB + CC))),2) 
FROM tbl t 
INNER JOIN ct1 
    ON t.employee = ct1.employee 
    AND t.account = ct1.account 
    AND t.fruit = ct1.fruit 
WHERE t.branch <> 'DD'