如何使查詢的字段在MySQL中是一個INT

Question

我在做這個查詢：

select tblagenda.ValorServicio, ((tblcopago.bonos + tblcopago.copago) * tblagenda.ValorServicio/grupo.Total) as Copago, grupo.Total 
    from tblcopago 
    inner join tblagenda on (tblagenda.CodigoOrden=tblcopago.CodigoOrden) 
    join (select sum(ValorServicio) as Total, CodigoOrden from tblagenda group by CodigoOrden) grupo on grupo.CodigoOrden = tblagenda.CodigoOrden 

我想Copago場是一個INT

Answer 1

如果你想圓結果：

SELECT ROUND((tblcopago.bonos + tblcopago.copago) * tblagenda.ValorServicio/grupo.Total) as Copago 

如果你想地板它（截斷至下INT）：

SELECT FLOOR((tblcopago.bonos + tblcopago.copago) * tblagenda.ValorServicio/grupo.Total) as Copago 

...如果你想上限值（截斷+ 1）：

SELECT CEIL((tblcopago.bonos + tblcopago.copago) * tblagenda.ValorServicio/grupo.Total) as Copago 

見MYSQL Mathematical Functions