1
我創建了一個它被按在我的主要活動保存按鈕如下調用方法的廣播:Alarmmanager不播或廣播接收機無法接收
public void scheduleAlarms(Context ctxt) {
String [] calvalue = (MessageDelay.getSelectedItem().toString()).split(" ", 3);
int H = Integer.parseInt(calvalue[1]);
Log.v("Timer","Timer"+H);
switch (H){
case 9:
H=9;
break;
case 12:
H=12;
break;
case 3:
H=15;
break;
case 5:
H=17;
break;
case 6:
H=18;
break;
case 8:
H=20;
break;
}
Calendar cal = Calendar.getInstance();
cal.set(Calendar.HOUR_OF_DAY, H);
cal.set(Calendar.MINUTE, 0);
cal.set(Calendar.SECOND, 0);
cal.set(Calendar.MILLISECOND, 0);
AlarmManager mgr=(AlarmManager)getSystemService(Context.ALARM_SERVICE);
Intent i=new Intent(getApplicationContext(), AlarmReceiver.class);
PendingIntent pi=PendingIntent.getService(getApplicationContext(), 0, i, 0);
mgr.setRepeating(AlarmManager.RTC,cal.getTimeInMillis(),AlarmManager.INTERVAL_DAY, pi);
Log.v("Timer","Timer");
}
然後我加入一行表現爲如下:
<receiver android:process=":remote" android:name=".AlarmReceiver"></receiver>
然後創建了一個接收器類,如下所示:
public class AlarmReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
try {
Toast.makeText(context, "broadcast received", Toast.LENGTH_SHORT).show();
// Set up new intent
Intent newIntent = new Intent(context, SendMessage.class);
// Start new intent
context.startService(newIntent);
} catch (Exception e) {
Toast.makeText(context, "There was an error somewhere, but we still received an alarm", Toast.LENGTH_SHORT).show();
e.printStackTrace();
}
}
}
但由於某種原因,當我在模擬器上測試它時,我無法接收任何廣播:(
任何人都可以請指教我我做錯了什麼?
提前
老兄你是天才,它的工作。我無法相信我在那裏犯了一個愚蠢的錯誤。非常感謝 :) –