for synset in wn.synsets(wordstr):
len_lemma_names = len (synset.lemma_names)
#print len_lemma_names, synset.lemma_names
count_lemma = count_lemma + len_lemma_names
for synset_scores in swn_senti_synset:
count_synset = count_synset + 1
#print count_synset, synset_scores
我想在count_synset前面打印len_lemma_names,但它不起作用。有沒有辦法將它們打印在一起?謝謝...Python:從不同的循環打印變量
'wn.synsets(wordstr)'和'swn_senti_synset'的長度是否一樣? – 2012-04-19 13:42:28
你的問題不清楚。你想要打印哪一行? count_ *變量在哪裏定義?他們都是什麼意思? – 2012-04-19 13:43:01
'synsets'和'swn_senti_synset'之間是否存在關係?或者您是否總是希望爲每個'synset_score'打印所有'len_lemma_names'? – BergmannF 2012-04-19 13:43:27