Python將不會從真正

Question

這是我的代碼，但正如標題所說，我不能打破，而打破，如果我把東西了，而在外面真和生命去低於0沒有任何反應。

from random import randint 
    import sys 
    value = int(randint(1,10)) 
    lives = int(5) 
    userinp = int(0) 
    if lives == 0: 
     print("no lives :(") 
    while True: 
     if lives != 0: 
      print(value) 
      print("You currently have: ", lives, " lives left") 
      userinp = input("Please enter a number from 1 to 10: ") 
      if int(userinp) == int(value): 
       print("Well done you wn :D") 
       sys.exit() 
      elif int(userinp) > int(value): 
       print("Your guess was too high please guess again") 
       lives = lives - 1 
      elif int(userinp) < int(value): 
       print("Your guess was too low please guess again") 
       lives = lives - 1 
    if lives == 0: 
     print("this") 

Answer 1

你必須打破while時lives == 0，或者由break或改變，同時條件。

Answer 2

一個while True是一個無限循環，消耗所有的CPU週期的100％，不會破壞 - 因爲當情況變得False一個while <condition>只結束，但絕不可能，因爲它總是True！

儘量不要打你循環的性質：

while True: 
    if lives != 0: 
     print(value) 
     print("You currently have: ", lives, " lives left") 
     userinp = input("Please enter a number from 1 to 10: ") 
     if int(userinp) == int(value): 
      print("Well done you wn :D") 
      sys.exit() 
     elif int(userinp) > int(value): 
      print("Your guess was too high please guess again") 
      lives = lives - 1 
     elif int(userinp) < int(value): 
      print("Your guess was too low please guess again") 
      lives = lives - 1 
    if lives == 0: # indent condition to fall within the loop 
     print("this") 
    if lives < 0: # add an extra case to handle what you want 
     break 

Answer 3

你的循環本質上是這樣的：

while True: 
    if lives != 0: 
     # do stuff with lives 

這是一個無限循環。即使lives == 0循環不會中斷，因爲此條件作爲循環塊的一部分進行測試，而不是循環條件。 你應該簡單地做：

while lives != 0: 
    # do stuff with lives 

甚至while lives > 0:的情況下，您管理期間1次循環迭代失去了數條生命（似乎不能夠在這裏，但有備無患）。

而且因爲你似乎想學習Python中，有可能要學習，還提高了其他一些東西：

無需整數這裏轉換爲整數：

value = int(randint(1,10)) 
lives = int(5) 
userinp = int(0) 

號如5和0和randint(1,10)本身就是整數。 "5"和"0"是包含一個數字作爲單個字符的字符串，在與整數進行比較之前需要進行轉換，但這裏不需要。 randint（）返回整數。

這是死代碼，因爲你已經設置lives到5 2線之上，而不是事後修改了它：

if lives == 0: 
    print("no lives :(") 

您應該檢查用戶是否確實輸入有效的整數轉換值，而不是任意的字符串： （continue會跳到下一個循環迭代，所以它會再次詢問用戶輸入的不遞減lives

userinp = input("Please enter a number from 1 to 10: ") 
if not userinp.isnumeric(): continue 

無需轉換ÿ我們已經一次又一次又一次整數value整數：

if int(userinp) == int(value): 

elif int(userinp) > int(value): 

elif int(userinp) < int(value): 

使用sys.exit()避免的，你可能只是break代替（走出循環，繼續。

最後，Python有得心應手-=, +=, *=, /=運營商，所以你可以寫的lives -= 1代替lives = lives - 1

Answer 4

這是我的解決方案，可以專門設置break情況如果發生特定事件時結束while循環。

while lives > 0: 
    print(value) 
    print("You currently have: ", lives, " lives left") 
    userinp = input("Please enter a number from 1 to 10: ") 
    if int(userinp) == int(value): 
     print("Well done you wn :D") 
     sys.exit() 
    elif int(userinp) > int(value): 
     print("Your guess was too high please guess again") 
     lives = lives - 1 
    elif int(userinp) < int(value): 
     print("Your guess was too low please guess again") 
     lives = lives - 1 


print("this")