訪問每個對象和分頁添加信息[CakePHP的3]

我想獲得分頁和JSON響應顯示之前修改對象，現在我的代碼如下所示：訪問每個對象和分頁添加信息[CakePHP的3]

$this->paginate = [ 
    'conditions' => $this->getPaginationConditions(), 
    ]; 
$this->set('reservations', $this->paginate($this->Reservations)); 
$this->set('_serialize', ['reservations']);

getPaginationConditions（）的外觀這樣

private function getPaginationConditions() 
{ 
    $conditions = ['Reservations.id_venue' => $this->Auth->user('id_venue_manager')]; 
    if ($date = $this->request->query('date')) { 
     $conditions['Reservations.date'] = $date; 
    } 
    if ($user = $this->request->query('id_user')) { 
     $conditions['Reservations.id_user'] = $user; 
    } 
    return $conditions; 
}

這將返回：

{ 
    "reservations": [ 
    { 
     "id_reservation": 139, 
     "reservation_type": "", 
     "date": "2017-09-04T00:00:00", 
     "time": "2017-03-01T10:00:00", 
     "id_venue": 1, 
     "id_user": 149, 
    }, 
    { 
     "id_reservation": 140, 
     "reservation_type": "", 
     "date": "2017-09-04T00:00:00", 
     "time": "2017-03-01T20:00:00", 
     "id_venue": 1, 
     "id_user": 149, 
    }, 
    [...]

我要訪問的每個對象遵循我在分頁之前的條件並添加一個「用戶」字段，我知道如何找到我的用戶，但我不知道如何訪問將通過分頁條件選擇的對象。它看起來像：

{ 
    "reservations": [ 
    { 
     "id_reservation": 139, 
     "reservation_type": "", 
     "date": "2017-09-04T00:00:00", 
     "time": "2017-03-01T10:00:00", 
     "id_venue": 1, 
     "id_user": 149, 
     "user" : { 
     "firstname" : "test", 
     "lastname" : "test", 
     "id_user" : "149", 
     [...] 
     } 
    }, 
    { 
     "id_reservation": 140, 
     "reservation_type": "", 
     "date": "2017-09-04T00:00:00", 
     "time": "2017-03-01T20:00:00", 
     "id_venue": 1, 
     "id_user": 149, 
     "user" : { 
     "firstname" : "test", 
     "lastname" : "test", 
     "id_user" : "149", 
     [...] 
     } 
    }, 
    [...]

感謝您的幫助！

來源

2017-03-01 Jonathan Bouchard

看來你沒有關注的CakePHP [命名轉換（https://book.cakephp.org/3.0/en/intro/conventions.html），你應該遵循CakePHP的命名轉換。這將有助於提高生產力 – tarikul05

您可以在$this->paginate上添加'contain'索引，傳遞要添加的模型關係。

<?php 
    $this->paginate = [ 
     'conditions' => $this->getPaginationConditions(), 
     'contain' => ['User'] 
    ]; 
?>

來源

2017-03-01 17:12:48

在調整了我的關聯後，我設法完成了這項工作，謝謝！ –

訪問每個對象和分頁添加信息[CakePHP的3]

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