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我創建了一個Boost.Python的包裝(用py ++)一個C++遺留類,需要一個HWND窗口句柄在其構造函數傳遞HWND。但是,當我嘗試使用它時將模塊導出到python後,出現類型不匹配錯誤。包裝與Boost.Python的
這裏是C++類我包裝:
// File Foo.hpp
//
#include "Windows.h"
class Foo
{
public:
Foo(const HWND window){}
virtual ~Foo(){}
virtual int Bar(int num) { return num; }
};
的PY ++輸出:
INFO Parsing source file "foo.hpp" ...
INFO gccxml cmd: ""c:\Program Files (x86)\gccxml 0.9\bin\gccxml.exe" -I"." "foo.hpp" -fxml="d:\temp\tmpdng3ts.xml""
INFO GCCXML version - 0.9(1.127)
INFO: file "generated_wrapper.cpp" - updated(0.001607 seconds)
生成的包裝:
#include "boost/python.hpp"
#include "foo.hpp"
namespace bp = boost::python;
struct Foo_wrapper : Foo, bp::wrapper<Foo> {
Foo_wrapper(::HWND const window)
: Foo(window)
, bp::wrapper<Foo>(){
// constructor
}
virtual int Bar(int num) {
if(bp::override func_Bar = this->get_override("Bar"))
return func_Bar(num);
else{
return this->Foo::Bar(num);
}
}
int default_Bar(int num) {
return Foo::Bar(num);
}
};
BOOST_PYTHON_MODULE(MyWrapper){
{ //::Foo
typedef bp::class_<Foo_wrapper> Foo_exposer_t;
Foo_exposer_t Foo_exposer = Foo_exposer_t("Foo", bp::init< HWND__ *>((bp::arg("window"))));
bp::scope Foo_scope(Foo_exposer);
bp::implicitly_convertible< const HWND, Foo >();
{ //::Foo::Bar
typedef int (::Foo::*Bar_function_type)(int) ;
typedef int (Foo_wrapper::*default_Bar_function_type)(int) ;
Foo_exposer.def(
"Bar"
, Bar_function_type(&::Foo::Bar)
, default_Bar_function_type(&Foo_wrapper::default_Bar)
, (bp::arg("num")));
}
}
}
在Python中我得到的不可─匹配錯誤:
>>> import MyWrapper
>>> import win32gui
>>> hwnd = win32gui.GetDesktopWindow()
>>> foo = MyWrapper.Foo(hwnd)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
Boost.Python.ArgumentError: Python argument types in
Foo.__init__(Foo, int)
did not match C++ signature:
__init__(struct _object *, struct HWND__ * window)
>>>
我怎樣才能解決這一問題,以便能夠在Python傳遞(從win32gui)窗口的句柄C++類,並與其互動?
環境: Visual Studio 2008中,升壓1.44,GCC-XML 0.9.0,PY ++ 1.0.0,1.1.0 pygccxml
謝謝,但我怎麼能'GetDesktopWindow'的INT輸出轉換成C++的HWND(無效*)? – Ehsan