我是新的使用aka流kafka(和akka流一般)。我正在嘗試構建一個圖表,以便將消息發佈到不同的主題。 如何將生產者作爲流連接以提交處理後的消息?我試着用Producer.flow但由於您使用的是GraphDSL我不能得到commitScaladsl
連接生產者流程圖
object TestFoo {
import akka.kafka.ProducerMessage.Message
implicit val system = ActorSystem("test-kafka")
implicit val materializer = ActorMaterializer()
val evenNumbersTopic = "even_numbers"
val allNumbersTopic = "all_numbers"
lazy val consumerSettings = ConsumerSettings(system, new StringDeserializer(), new JsonDeserializer[Int])
.withBootstrapServers("localhost:9092")
.withGroupId("group1")
.withProperty(ConsumerConfig.AUTO_OFFSET_RESET_CONFIG, "earliest")
lazy val source = Consumer.committableSource(consumerSettings, Subscriptions.topics(Set(evenNumbersTopic, allNumbersTopic)))
val producerSettings = ProducerSettings(system, new StringSerializer(), new StringSerializer())
.withBootstrapServers("localhost:9092")
val flow: RunnableGraph[NotUsed] = RunnableGraph.fromGraph(GraphDSL.create() { implicit b =>
import akka.stream.scaladsl.GraphDSL.Implicits._
type TypedMessage = Message[String, Int,CommittableOffset]
val bcast = b.add(Broadcast[TypedMessage](2))
val merge = b.add(Merge[TypedMessage](2))
val evenFilter = Flow[TypedMessage].filter ( c => c.record.value() % 2 == 0)
val justEven = Flow[TypedMessage].map{
case Message(pr, offset) =>
val r = new ProducerRecord[String, Int]("general", pr.value())
Message(r, offset)
}
val allNumbers = Flow[TypedMessage].map{
case Message(pr, offset) =>
val r = new ProducerRecord[String, Int](allNumbersTopic, pr.value())
Message(r, offset)
}
val toMsg = Flow[ConsumerMessage.CommittableMessage[String, Int]].map{ msg =>
val r = new ProducerRecord[String, Int]("general", msg.record.value())
Message(r, msg.committableOffset)
}
source ~> toMsg ~> bcast
bcast ~> evenFilter ~> justEven ~> merge
bcast ~> allNumbers ~> merge
merge ~> Producer.flow(producerSettings).mapAsync(producerSettings.parallelism) { result =>
result.message.passThrough.commitScaladsl() //this doesn't compile, cannot get the .commitScaladsl()
}
ClosedShape
})}
此刻這個例子是操縱着許多其他編譯錯誤。你能修改它,使你的編譯錯誤很容易重現嗎? –
@StefanoBonetti是的,我更新了代碼,但編譯錯誤較少,謝謝 – igx