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我正在mongodb php應用程序中執行聚合命令,如下面的代碼行。如何從mongo數據庫聚合結果中刪除waitedMS並確定?
<?php
$query = array('$or' => array(
array('employeeList'=>array('$exists' => false)),
array('employeeList'=>array('$eq' => null)),
array('employeeList'=>array('$eq' => ",")),
array('employeeList'=>array('$eq' => ""))
));
$pipeline = array(
array(
'$match' => $query
),
array(
'$lookup' => array(
'from' => 'userTbl',
'localField' => 'user_id',
'foreignField' => 'uid',
'as' => 'userdetails'
)
),
);
$output = $this->db->broadcastTbl->aggregate($pipeline);
$result =array();
array_push($result, $output);
現在的輸出顯示爲
[{"waitedMS":0,"result":[{"_id":{"$id":"58d7a6561d78597411000029"},"broadcast_id":35,"studentList":"","employeeList":"999","mailTitle":"hello","broadcastMessage":"how","emailSent":"0","userdetails":[]},{"_id":....
...
"ok":1}]
我想刪除 「waitedMS」:0。 「結果」:和「ok」:1來自json。輸出應該像
[{"_id":{"$id":"58d7a6561d78597411000029"},"broadcast_id":35,"studentList":"","employeeList":"999","mailTitle":"hello","broadcastMessage":"how","emailSent":"0","userdetails":[]}, ...
]
請幫助我!
我沒有在這裏看到任何輸出,但不會是'$ output [「result」]'然後呢? – miken32
你是絕對正確的,但現在正在顯示爲[[...]],我想[0123] []] – Nida
[我如何從PHP提取JSON數據?](http:// stackoverflow。 COM /問題/ 29308898 /如何-DO-I-提取數據從 - JSON-與-PHP) – miken32