JSON沒有正確地通過php插入到mysql

我一直試圖通過php將json文件中的數據插入到mysql中。我有一個功能在一個文件中插入，而解碼在另一個文件中完成。當我運行的代碼，我收到此錯誤：JSON沒有正確地通過php插入到mysql

You could not be registered due to a system error. We apologize for any inconvenience. 

Column 'password' cannot be null 

Query: INSERT INTO users (id, email, password, username, deviceId, date_created) VALUES (null, ?, ?, ?, ?, NOW()) 
Query was executed 

enter code here

這裏是我的三個文件：

insertion.php：

//Require files 
require('functions.php'); 
if(file_exists('data.json')){ 
    echo "The file exists "; 

    $file= file_get_contents('data.json'); 
    echo json_encode('data.json'); 

    $data=json_decode($file, true); 

    var_dump($data); 

$email= $data["email"]; 
$password= $data["password"]; 
$username= $data["username"]; 
$deviceId= $data["deviceId"]; 
$tableName= 'users'; 
$email= "[email protected]"; 

$error=json_last_error(); 
echo "<br><br>"; 
echo "your email shoudl be displayed right here: ".$email. "This is email"; 
echo "<br>JSON Errors will display here:". $error; 

$execute= dataInsert($tableName, $email, $password, $username, $deviceId); 

if($execute){ 
    echo "Query was executed"; 


} 



} 
else{ 

echo "file does not exist"; 

}

的functions.php：

//------------------------dataInsert()---------------------------// 

function dataInsert($tableName, $email, $password, $username, $deviceId){ 


//set database connection 
require('mysqli_connect.php'); 
if($dbc){ 
    echo "<h3>connection successful</h3>"; 

} 

//form query using the values and tablename 
$query = "INSERT INTO users (id, email, password, username, deviceId, date_created) 
VALUES (null, ?, ?, ?, ?, NOW())"; 


//Prepare statement 
$stmt= mysqli_prepare($dbc, $query); 


//Bind the variables 

mysqli_stmt_bind_param($stmt, 'sssi', $email, $password, $username, $deviceId); 


//Execute the query 

$result=mysqli_stmt_execute($stmt); 



if($result){ 
    echo "Success !"; 

} 
else{ 
    // Public message: 
     echo 'System Error 
     <p class="error">You could not be registered due to a system error. We apologize for any inconvenience.</p>'; 

     // Debugging message: 
     echo '<p>' . mysqli_error($dbc) . '<br /><br />Query: ' . $query . '</p>'; 

} 

mysqli_close($dbc); // Close the database connection. 
return true; 
}

data.json

<pre> 
<code> 
{"users":[ 
{ 
    "email":"[email protected]", 
    "password":"mypass12", 
    "username":"myusername", 
    "deviceId":"21" 
} 

]}

當我用var_dump顯示JSON數組，它看起來是正確的：

"data.json"array(1) { ["users"]=> array(1) { [0]=> array(4) { ["email"]=> string(19) "[email protected]" ["password"]=> string(6) "mypass12" ["username"]=> string(13) "myusername" ["deviceId"]=> string(2) "21" } } }

我已經能夠將行插入數據庫中，但他們都是空白的，除了日期和汽車增量ID。當我設置$ email = [email protected]時，它將顯示密碼不能爲空，但註釋該行將導致錯誤顯示'電子郵件'不能爲空

來源

2016-06-28 Fritz

嘗試刪除ID在查詢中插入 – claudios

我刪除在插入ID和空自的值，但我仍然得到相同的錯誤 – Fritz

也嘗試刪除查詢參數date_created – claudios

您正在爲您的ID字段插入空值。嘗試刪除。

來源

2016-06-28 01:30:48 Savetti

您正在錯誤地訪問解碼的json字符串的值，傳遞true作爲json_decode的第二個值，您將獲得一個關聯數組。

var_dump($data['users'][0]['email']);

結果

[email protected]

所以你可以做這樣的事情

if (count($data['users'])) 
{ 
    foreach($data['users'] as $user) 
    { 
     // insert query passing 
     // $user['email'], $user['password'], 
     print $user['email']; 
    } 
}

來源

2016-06-28 01:49:20 juliusbin

JSON沒有正確地通過php插入到mysql

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