我有這樣的對象數組;按數組排序對象數組
var orders = [
{
status: "pending"
},
{
status: "received"
},
{
status: "sent"
},
{
status: "pending"
}
]
我想解決這陣基礎上status鍵的值的對象，但使對象的順序status鍵的可能值的排列順序相匹配;
var statuses = ["pending", "sent", "received"]
因此，排序後，兩個"pending"對象將是第一，其次是"sent"對象，最後是"received"對象。
我該怎麼做？
你可以用sort()和indexOf()來做到這一點。
var orders = [{
status: "pending"
}, {
status: "received"
}, {
status: "sent"
}, {
status: "pending"
}]
var statuses = ["pending", "sent", "received"]
var result = orders.sort(function(a, b) {
return statuses.indexOf(a.status) - statuses.indexOf(b.status)
})
console.log(result)可以使用sort()功能：
var statuses = ["pending", "sent", "received"];
var orders = [
{
status: "pending"
},
{
status: "received"
},
{
status: "sent"
},
{
status: "pending"
}
];
orders.sort(function(a, b) {
return statuses.indexOf(a.status) - statuses.indexOf(b.status);
});
console.log(orders);使用Array#sort方法對象的數組排序。在哪裏使用對象來存儲密鑰的索引，這有助於避免使用方法（這是較慢的）。
var orders = [{
status: "pending"
}, {
status: "received"
}, {
status: "sent"
}, {
status: "pending"
}];
var statuses = ["pending", "sent", "received"];
// generate the object which holds the index in array
// or use an object instead of array which holds the index
var index = statuses.reduce(function(obj, k, i) {
obj[k] = i;
return obj;
}, {})
console.log(
orders.sort(function(a, b) {
return index[a.status] - index[b.status];
})
)你可以使用一個對象作爲哈希表的排序順序。
var orders = [{ status: "pending" }, { status: "received" }, { status: "sent" }, { status: "pending" }],
statuses = { pending: 1, sent: 2, received: 3 };
orders.sort(function (a, b) {
return statuses[a.status] - statuses[b.status];
});
console.log(orders);可以用這樣的方法indexOf()排序回調之內，但更有效的是要建立第一
var statIndex = statuses.reduce(function(a,c,i){
a[c] = i;
return a
},{})
orders.sort(function(a,b){
return statIndex[a.status] - statIndex[b.status]
})
這將是更好，如果'statuses'是一個對象的索引的HashMap中，狀態名稱是屬性名稱，屬性的值是分類權重。然後你的排序比較功能可能會差異的價值。 – Pointy