我正在使用POST方法逐個插入新記錄,但我期望一次推送多個記錄。我對單個插入代碼如下:如何在使用Spring-data-JPA的crudRepository中追加MySQL數據庫中的多條記錄?
@RequestMapping(path="/users")
public class MainController {
@Autowired
private UserRepository userRepository;
@PostMapping(path="/add", consumes="application/json", produces = "application/json")
@Transactional(propagation=Propagation.REQUIRED)
public @ResponseBody String addNewUser(@RequestBody UserFormDto userForm) {
User n = new User();
n.setName(userForm.getName());
n.setEmail(userForm.getEmail());
userRepository.save(n);
return "\n\t\t Saved";
}
}
實體類如下:任何幫助將非常appriciatted
package hello;
import javax.persistence.*;
import javax.persistence.Table;
import org.hibernate.validator.constraints.Email;
@SuppressWarnings("unused")
@Entity
public class User {
private String name;
private String email;
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private Long id;
public User() {
}
public User(String email,String name) {
super();
this.name = name;
this.email = email;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
}
你從哪裏得到多個用戶?你的方法addNewUser()只有一個用戶。 –
可能的重複:https://stackoverflow.com/questions/32793403/crudrepository-and-hibernate-savelists-vs-saveentity-in-transaction –