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我想在我的urls.py中引用一個包含在同一個urls.py文件中的另一個urls。Django包含單個urls.py
我的結構如下:
├── docs
├── requirements
├── scripts
└── sonata
├── person
│ ├── migrations
│ ├── templatetags
│ └── urls.py
├── registration
│ ├── migrations
│ └── urls.py
└── sonata
├── settings
└── urls.py
我要每個來的網址前綴「PDF /」添加一個值來kwargs並再次調用URL的其餘部分。這是我的嘗試:
urlpatterns = patterns('',
url(r'^$',TemplateView.as_view(template_name='registration/login.html')),
# This is my attempt for capturing the pdf prefix
# and calling this same file afterwards with the pdfOutput variable set to True
url(r'^pdf/', include('sonata.urls'), kwargs={'pdfOutput':True}),
url(r'^admin/', include(admin.site.urls)),
url(r'^person/', include('person.urls')),
url(r'^registration/', include('registration.urls')),
url(r'^menu/', registration_views.menu, name='menu'),
url(r'^customers/', person_views.customers, name='customers'),
url(r'^employees/', person_views.employees, name='employees'),
url(r'^alumns/', person_views.alumns, name='alumns'),
url(r'^teaching/', person_views.docencia, name='teaching'),
url(r'^i18n/', include('django.conf.urls.i18n')),
)
有沒有這樣做的方法?我看了文檔。似乎很清楚如何傳遞值,但是在證明我不能使包含之後。 (我不希望包含()數組模式重複所有的URL,這將打破DRY原則)。
預先感謝
謝謝。現在這裏已經太晚了。我會很快測試這個。 – madtyn 2015-04-05 22:40:30