將PHP/HTML下拉菜單轉換爲單選按鈕

Question

目前我有一個下拉菜單循環（循環取決於每個頁面的結果，我可以定義，你可以看到爲什麼我會使用循環），我想將下拉菜單變成單選按鈕。以下是我的代碼。你可以給我一些關於如何將其轉換的指示嗎？

if (isset($_POST['formSubmit'])){ 
    $rating = $_POST['rating']; 
    $accountID = $_POST['accountID']; 

    $query = mysql_query("UPDATE Spreadsheet SET rating='$rating' WHERE accountID='$accountID'"); 
} 

while ($row = mysql_fetch_array($query)){ 

    ?> 

<form name ="rating" method ="POST" action ="" > <? 

echo "<input type = 'hidden' name = 'accountID' value = '" . $row['accountID'] . "' >"; 

?> 
    <select name="rating"> 

     <? 

     $values = array('0 - No rating','1 - Very Bad','2 - Bad','3 - Average','4 - Above Average'); 

     for ($i =0; $i < count($values); $i++){ 
      echo "<option value = \"$i\""; 

      if ($row['rating'] == $i) { 
       echo "selected=\"selected\""; 
      } 

      echo ">" . $values[$i] . "</option>"; 

     } 

     ?> 

     </select> 
     <input type ="Submit" name ="formSubmit" value ="Submit" /> 
     </form> 

Answer 1

 $values = array('0 - No rating','1 - Very Bad','2 - Bad','3 - Average','4 - Above Average'); 


    <form name ="rating" method ="POST" action ="" > 
    <? 
    echo "<input type = 'hidden' name = 'accountID' value = '" . $row['accountID'] . "' >"; 
    for($i =0; $i < count($values); $i++) 
    { 
    ?> 
    <input type="radio" name="rbl" value="<?php echo $row['rating']; ?>" id="rbl_<?php echo $i; ?>" <? if($row['rating'] == $i) echo "checked='checked'"; ?>/> 

<label for="rbl_<?php echo $i; ?>"><?php echo $value[$i]; ?></label> 


    <? } ?> 

      <input type ="Submit" name ="formSubmit" value ="Submit" /> 
      </form>