獲取類別名稱和類別鏈接裏面的循環在WordPress

Question

有沒有一種方法獲取類別的名稱和鏈接到類別頁分開在wordpress循環內。我沒有該類別的id，我想顯示圖像而不是類別名稱，因此the_category（）不適用於我。

感謝

感謝所有的答案..

Answer 1

get_the_category()作品。使用這個，你將得到循環當前正在處理的每個帖子的類別對象數組。例如：

//the loop 
$categories = get_the_category(); 
//the loop cont.... 
var_dump($categories); 
    array 
     0 => 
     object(stdClass)[191] 
      public 'term_id' => &string '1' (length=1) 
      public 'name' => &string 'Uncategorized' (length=13) 
      public 'slug' => &string 'uncategorized' (length=13) 
      public 'term_group' => string '0' (length=1) 
      public 'term_taxonomy_id' => string '1' (length=1) 
      public 'taxonomy' => string 'category' (length=8) 
      public 'description' => &string '' (length=0) 
      public 'parent' => &string '0' (length=1) 
      public 'count' => &string '1' (length=1) 
      public 'object_id' => string '66' (length=2) 
      public 'cat_ID' => &string '1' (length=1) 
      public 'category_count' => &string '1' (length=1) 
      public 'category_description' => &string '' (length=0) 
      public 'cat_name' => &string 'Uncategorized' (length=13) 
      public 'category_nicename' => &string 'uncategorized' (length=13) 
      public 'category_parent' => &string '0' (length=1) 
     1 => 
     object(stdClass)[190] 
      public 'term_id' => &string '3' (length=1) 
      public 'name' => &string 'asd' (length=3) 
      public 'slug' => &string 'asd' (length=3) 
      public 'term_group' => string '0' (length=1) 
      public 'term_taxonomy_id' => string '3' (length=1) 
      public 'taxonomy' => string 'category' (length=8) 
      public 'description' => &string '' (length=0) 
      public 'parent' => &string '0' (length=1) 
      public 'count' => &string '1' (length=1) 
      public 'object_id' => string '66' (length=2) 
      public 'cat_ID' => &string '3' (length=1) 
      public 'category_count' => &string '1' (length=1) 
      public 'category_description' => &string '' (length=0) 
      public 'cat_name' => &string 'asd' (length=3) 
      public 'category_nicename' => &string 'asd' (length=3) 
      public 'category_parent' => &string '0' (length=1) 

現在你可以通過每個類別重複，像這樣

foreach($categories as $category){ 
    echo $category->name; //category name 
    $cat_link = get_category_link($category->cat_ID); 
    echo '<a href="'.$cat_link.'">'.$category->name.'</a>'; // category link 
} 

Answer 2

您可以使用：

$category = get_the_category(); 
echo '<a href="'.get_category_link($category[0]->cat_ID).'"><img src="'.$category[0]->cat_name.'" alt="'.$category[0]->cat_name.'" /></a>'; 

我認爲這會幫助你

或者：

foreach(get_the_category() as $category) 
{ 
    echo '<a href="'.get_category_link($category->cat_ID).'"><img src="'.$category->cat_name.'" alt="'.$category->cat_name.'" /></a>'; 
} 

用get_the_category()即可獲得該類別，並使用get_category_link()即可獲得該類別的鏈接。

我希望這可以幫助你:)在循環

Answer 3

在循環

<?php 
global $post; 
$categories = get_the_category($post->ID); 
$cat_link = get_category_link($category[0]->cat_ID); 
echo '<a href="'.$cat_link.'">'.$categories[0]->cat_name.'</a>' 
?> 

Answer 4

我認爲戰略中的代碼應該改變像這樣：

<?php 
global $post; 
$categories = get_the_category($post->ID); 
$cat_link = get_category_link($categories[0]->cat_ID); 
echo '<a href="'.$cat_link.'">'.$categories[0]->cat_name.'</a>' 
?> 

$ category s應該是$類別，那麼它適用於我

Answer 5

此代碼是好的，除非你忘了把另一個;在鏈路的末端

echo <a href="'.$cat_link.'">'.$categories[0]->cat_name.'</a> 

應該

echo '<a href="'.$cat_link.'">'.$categories[0]->cat_name.'</a>' ;