Java不會停止循環我的if語句

Question

這可能是一個明顯的答案，但它明天到期了，我完全被難住了。除了最後的if語句之外，一切都很好。看起來continueGame循環無限循環了if語句。如果有人可以幫我解決這個問題，請。

import java.util.Random; 
import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStreamReader; 


public class HighLOw { 
    public static void main(String[] args) throws IOException { 

     String input = null; 
     int number = 0; 
     int tries = 0; 
     boolean highorlow = false; 
     boolean continueGame = false; 
     boolean validInput = false; 
     Random random = new Random(); 
     int randomNumber = (random.nextInt(101)); 

     System.out.println("Welcome to the High/Low game."); 
     System.out.println("Guess a number between 0 and 100."); 
     System.out.println(
       "In order to print a random number, type your number in the console and press enter."); 
     System.out.println("Keep going until you get the right number."); 
     System.out.println("Have fun."); 
     System.out.println(randomNumber); 

     while (continueGame == false) { 

      while (validInput == false) { 
       try { 
        BufferedReader bufferedReader = new BufferedReader(
          new InputStreamReader(System.in)); // BufferedReader variable where the user will input their answer 

        input = bufferedReader.readLine(); 
        number = Integer.parseInt(input); 
        validInput = true; 

       } catch (NumberFormatException ex) { 
        System.out.println("Invalid input, please enter a number."); 
        validInput = false; 
       } 

       if (number < 0 || number > 100) { 
        System.out.println(
          "Error, you must enter a number that is between 0 and 100"); 
        validInput = false; 
       } 
      } 

      if (number < randomNumber) { 
       System.out.println(
         number + " is too low. Please try a higher number"); 
       tries++; 
       highorlow = false; 
      } else if (number > randomNumber) { 
       System.out.println(
         number + " is too high. Please try a lower number"); 
       tries++; 
       highorlow = false; 
      } else if (number == randomNumber) { 
       System.out.println(
         "Congratulations, you guessed the right number. Now go outside."); 
       tries++; 
       System.out.println("It took you " + tries + (" tries.")); 
       System.out.println("Game Ended"); 
       continueGame = true; 
      } 
     } 
    } 
} 

Answer 1

一些提示：當您進入首次有效數字，validInput將成爲true。然後，代碼繼續比較number到randomNumber，然後再次跳轉到continueGame循環的開始。 validInput現在的價值是多少，這對validInput循環會有什麼影響？ number會獲得新的價值嗎？

而且你不需要做while (validInput == false) ..只要while (!validInput)相當於..

Answer 2

記住if/else語句是從頂部評估，以底部。一旦匹配if被發現，其身體被執行並退出。

記住這一點，這意味着if/else結構的給定評估僅有一個case，其中主體將被執行。

看看你if條款，想想他們像許多行（或更好，但繪製什麼number和randomNumber可能是一些例子號線），看看答案在你跳出。