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編譯時，我收到以下錯誤消息，但我確定我有在外部Project2.c文件中聲明的變量。有人能給我提示我做錯了什麼嗎？謝謝錯誤'extern'使用 - 無法解析的外部符號
1>main.obj : error LNK2001: unresolved external symbol _num_days
1>main.obj : error LNK2019: unresolved external symbol _countDays referenced in function _testIt
1>main.obj : error LNK2001: unresolved external symbol _what_birthday
1>main.obj : error LNK2001: unresolved external symbol _birth_day
1>main.obj : error LNK2001: unresolved external symbol _birth_month
1>main.obj : error LNK2001: unresolved external symbol _birth_year
的源代碼：
#include <stdio.h>
/* the following five variables are defined inside project2.c */
extern int birth_year;
extern int birth_month;
extern int birth_day;
extern int what_birthday;
extern int num_days;
void countDays(void); // a declaration of your function
int num_tests_passed = 0;
void testIt(int test_num,
int year, int month, int day, int bday, int expected) {
birth_year = year;
birth_month = month;
birth_day = day;
what_birthday = bday;
countDays();
printf("your answer to test %d was %d, should have been %d\n",
test_num, num_days, expected);
/* check the correctness and quality of their solution */
if (num_days == expected) {
if ((birth_year == year) && (birth_month == month)
&& (birth_day == day)) {
num_tests_passed += 1;
} else {
printf("you got the answer correct,"
"but you don't follow instructions very well\n");
}
} else {
printf("oops.\n");
}
}
int main(void) {
/* test #1: Born Feb 4, 1964 and about to turn 41 */
testIt(1, 1964, 2, 4, 41, 41 * 365 + 11); // feb 29ths in '64, 68, 72,
// 76, 80, 84, 88, 92, 96, 00, and 04 (11 days)
/* test #2: Born Jan 22, 1998 and about to turn 2 */
testIt(2, 1998, 1, 22, 2, 2 * 365); // no leap days
/* test #3: Born March 22, 1998 and about to turn 2 */
testIt(3, 1998, 3, 22, 2, 2 * 365 + 1); // feb 29, 2000
/* test #4: Born March 22, 1898 and about to turn 2 */
testIt(4, 1898, 3, 22, 2, 2 * 365); // no leap days
/* test #5: Born Jan 22, 1996 and about to turn 4 */
testIt(5, 1996, 1, 22, 4, 4 * 365 + 1); // feb 29, 1996
/* test #6: Born March 22, 1996 and about to turn 4 */
testIt(6, 1996, 3, 22, 4, 4 * 365 + 1); // feb 29, 2000
/* test #7: Born March 22, 1796 and about to turn 4 */
testIt(7, 1796, 3, 22, 4, 365 * 4); // no leap days
/* test #8: Born Jan 1, 1800 and about to turn 101 */
testIt(8, 1800, 1, 1, 101, 101 * 365 + 24); // There are 26 years divisible by 4
// between 1800 and 1901, all of these except 1800 and 1900 are leap years
// so there are 24 leap days
/* test #9: born Jan 1, 1900 and about to turn 100 */
testIt(9, 1900, 1, 1, 100, 100 * 365 + 24); // 26 years divisible by 4
// 1900 was not a leap year, and the 100th brithday comes
// before Feb 29, 2000, so only 24 leap days.
if (num_tests_passed == 9) {
printf("all tests passed successfully. Well done!\n");
} else {
printf("you only passed %d of the 9 tests. Looks like you've got some work to do\n",
num_tests_passed);
}
}
我們需要查看鏈接命令。 – 2009-12-22 00:37:15
您可以將此C文件編譯爲目標文件（.o文件），但不是可執行文件，除非將其鏈接到其他必需的文件。 – Artelius 2009-12-22 00:40:31