0
鑑於這種方法調用:遞歸在java中
public class MainClass {
public static void main(String[] args) {
System.out.println(fib(3));
}
private static int fib(int i) {
System.out.println("Into fib with i = " + i);
if (i < 2) {
System.out.println("We got here");
return i;
}
return fib(i-1) + fib(i-2);
}
}
我預計:
* fib(i-1) to return 2
* fib(i-2) to return 1
* return 2 + 1 to return 3
結果:
2
這是控制檯輸出:
Into fib with i = 3
Into fib with i = 2
Into fib with i = 1
We got here
Into fib with i = 0
We got here
我明白了一切到這部分:
Into fib with i = 0
何時能拿到我曾經去過0?
ahhhh我看到了,謝謝 – JohnMerlino 2012-07-16 01:42:10
解決它,只需用「return 1」替換語句「return i」 – CosmicComputer 2012-07-16 01:54:23
這個函數重現了斐波那契公式,它以0開頭,因此它首先返回0。我的問題。 – JohnMerlino 2012-07-16 01:55:56