一次獲取字符組nn

Question

我試圖用一次三個字符串（但可以是任意數字）對字符串進行分組。使用此代碼：

"this gets three at a time".scan(/\w\w\w/) 

我得到：

["thi","get","thr","tim"] 

但是我想要得到的是：

["thi","sge","tst","hre","eat","ati","me"] 

Answer 1

\w匹配的字母數字和下劃線（即它是[a-zA-Z0-9_]速記），而不是空格。儘管如此，它並沒有奇蹟般地跳過空格，正如你所期望的那樣。

所以，你首先必須把空格去掉：

"this gets three at a time".gsub(/\s+/, "").scan(/.../) 

或非單詞字符：

"this gets three at a time".gsub(/\W+/, "").scan(/.../) 

你的三個字符匹配之前。

雖然你應該寧願使用

"this gets three at a time".gsub(/\W+/, "").scan(/.{1,3}/) 

也獲得最後1或2，如果長度不被3整除

Answer 2

"this gets three at a time".tr(" \t\n\r", "").scan(/.{1,3}/) 

Answer 3

您可以嘗試以下以及：

sentence = "this gets three at a time" 
sentence[" "] = "" 
sentence.scan(/\w\w\w/) // no change in regex 

或者：

sentence = "this gets three at a time" 
sentence[" "] = "" 
sentence.scan(/.{1,3}/) 

或者：

sentence = "this gets three at a time" 
sentence[" "] = "" 
sentence.scan(/[a-zA-Z]{1,3}/)