我正在使用下面的代碼來提取Java中的zip文件。我應該如何提取java中的壓縮文件夾?
import java.io.*;
import java.util.zip.*;
class testZipFiles
{
public static void main(String[] args)
{
try
{
String filename = "C:\\zip\\includes.zip";
testZipFiles list = new testZipFiles();
list.getZipFiles(filename);
}
catch (Exception e)
{
e.printStackTrace();
}
}
public void getZipFiles(String filename)
{
try
{
String destinationname = "c:\\zip\\";
byte[] buf = new byte[1024];
ZipInputStream zipinputstream = null;
ZipEntry zipentry;
zipinputstream = new ZipInputStream(
new FileInputStream(filename));
zipentry = zipinputstream.getNextEntry();
while (zipentry != null)
{
//for each entry to be extracted
String entryName = zipentry.getName();
System.out.println("entryname "+entryName);
int n;
FileOutputStream fileoutputstream;
File newFile = new File(entryName);
String directory = newFile.getParent();
if(directory == null)
{
if(newFile.isDirectory())
break;
}
fileoutputstream = new FileOutputStream(
destinationname+entryName);
while ((n = zipinputstream.read(buf, 0, 1024)) > -1)
fileoutputstream.write(buf, 0, n);
fileoutputstream.close();
zipinputstream.closeEntry();
zipentry = zipinputstream.getNextEntry();
}//while
zipinputstream.close();
}
catch (Exception e)
{
e.printStackTrace();
}
}
}
顯然,由於break語句,這不會提取文件夾樹。我試圖用遞歸來處理文件夾樹,但失敗了。有人可以告訴我如何改進此代碼來處理文件夾樹而不是壓縮的單個級別文件夾。
Chathuranga:Emre的答案是否解決了您的問題?如果是這樣,通過檢查他的答案謝謝他=) – mikek 2009-06-17 10:57:46