從字符串中提取子串

Question

在谷歌，BigQuery中，我需要拉即域之間的串**和**如示例波紋管 的字符串是列在「Site_Data」

燦誰來幫幫我？ 10倍！

Answer 1

參見下面的例子

#standardSQL 
WITH yourTable AS (
    SELECT '756-1__6565656565656, tagtype**unmapped,domain**www.sport.com,userarriveddirectly**False' AS Site_Data 
) 
SELECT 
    REGEXP_EXTRACT(Site_Data, r'domain\*\*(.*)\*\*') AS x, 
    Site_Data 
FROM yourTable 

Answer 2

是否所有的琴絃有格式？假設您總是需要**定界符後面的第三個字符串，有幾個不同的選項。

1）使用SPLIT，如：

#standardSQL 
WITH SampleData AS (
    SELECT '756-1__67648582789116,tagtype**unmapped,domain**www.sport.com,userarriveddirectly**False' AS site_data 
) 
SELECT SPLIT(site_data, '**')[OFFSET(2)] AS visit_type 
FROM SampleData; 

2）使用REGEXP_EXTRACT，如：

#standardSQL 
WITH SampleData AS (
    SELECT '756-1__67648582789116,tagtype**unmapped,domain**www.sport.com,userarriveddirectly**False' AS site_data 
) 
SELECT REGEXP_EXTRACT(site_data, r'[^\*]+\*\*[^\*]+\*\*([^\*]+)') AS visit_type 
FROM SampleData; 

採取此基礎上更進一步，如果你想分裂域和到達類型，您可以再次使用SPLIT：

#standardSQL 
WITH SampleData AS (
    SELECT '756-1__67648582789116,tagtype**unmapped,domain**www.sport.com,userarriveddirectly**False' AS site_data 
) 
SELECT 
    SPLIT(visit_type)[OFFSET(0)] AS domain, 
    SPLIT(visit_type)[OFFSET(1)] AS arrival_type 
FROM (
    SELECT SPLIT(site_data, '**')[OFFSET(2)] AS visit_type 
    FROM SampleData 
);