我在我的應用程序中使用JPA,它在我查詢對象後工作,但是一旦我嘗試保存或更新對象時會拋出錯誤javax.persistence.TransactionRequiredException: No transactional EntityManager available
。無法使用JPA在彈簧中保存/更新實體
這是Java配置:
@Configuration
@EnableTransactionManagement(proxyTargetClass = true)
@PropertySource("classpath:dao.properties")
public class JpaConfig {
@Autowired
private Environment env;
@Bean
public DataSource dataSource() {
BasicDataSource dataSource = new BasicDataSource();
.....................
return dataSource;
}
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
Properties jpaProperties = new Properties();
jpaProperties.put("hibernate.dialect", ...........)
LocalContainerEntityManagerFactoryBean entityManagerFactoryBean = new LocalContainerEntityManagerFactoryBean();
entityManagerFactoryBean.setDataSource(dataSource());
entityManagerFactoryBean.setJpaVendorAdapter(new HibernateJpaVendorAdapter());
entityManagerFactoryBean.setJpaProperties(jpaProperties);
entityManagerFactoryBean.setPackagesToScan("com....");
return entityManagerFactoryBean;
}
@Bean
public PlatformTransactionManager transactionManager(EntityManagerFactory emf) {
JpaTransactionManager transactionManager = new JpaTransactionManager();
transactionManager.setEntityManagerFactory(emf);
return transactionManager;
}
}
注意我在@EnableTransactionManagement
使用proxyTargetClass = true
,因爲我不希望在我的應用程序來創建無用的接口。
這是道的具體FPGA實現:
@Transactional
@Repository
public abstract class AbstractJPADao<I, E> {
@Autowired
@PersistenceContext
protected EntityManager entityManager;
private Class<E> type;
public AbstractJPADao() {
type=....
}
@Override
public Result<E> find(I id) {
E e = entityManager.find(type, id);
return Result.newInstance().setContent(e);
}
@Override
public Result<E> find(Map<String, Object> condition) {
Query q = entityManager.createQuery(".......));
return Result.newInstance().setContent(q.getResultList());
}
@Override
public E save(E element) {
entityManager.persist(element);
return element;
}
@Override
public E update(E element) {
entityManager.merge(element);
return element;
}
@Override
public void delete(E element) {
entityManager.remove(element);
}
}
@Repository
@Transactional
public class DepartmentDao extends AbstractJPADao<String, Department> {
@Override
protected String selectCause(Map<String, Object> condition) {
return "";
}
}
而控制器作爲道的客戶端:
@Controller
@RequestMapping("/api/deps")
public class DepartmentCtrl {
@Autowired
private DepartmentDao departmentDao;
@RequestMapping(value = "", method = RequestMethod.POST)
public Result create(@Valid Department department, BindingResult bindingResult) {
if (!bindingResult.hasErrors()) {
departmentDao.save(department);
return Result.newInstance().setContent(department);
}
throw new RuntimeException("...");
}
}
這有什麼錯?
dao.properties:
jdbc.driverClassName=com.mysql.jdbc.Driver
jdbc.url=jdbc:mysql://localhost:3306/proj
jdbc.username=root
jdbc.password=
hibernate.dialect=org.hibernate.dialect.MySQL5Dialect
hibernate.hbm2ddl.auto=update
#hibernate.ejb.naming_strategy=true
hibernate.show_sql=true
hibernate.format_sql=true
爲什麼'AbstractJPADao'中有兩個註解'@ Autowired'和'@ PersistenceContext' 'EntityManager'類型的'protected'字段? – Tiny
''JpaConfig'中提供'EntityManager'作爲一個bean,應該被注入'AbstractJPADao'。 – hguser
你在哪個容器中運行? –