遍歷並比較2個數組列表並找到匹配項

Question

我有2個數組列表。我想返回兩者之間的唯一值。這是如何完成的？

String[] s1 = {10, 1}; 
String[] s2 = {10, 1, 13}; 

//loop through and compare element of s1 to s2  
//switch varialbe used to indicate whether a match was found 
boolean matchFound = false; 

//outer loop for all the elements in s2 
for (int i = 0; i < s2.lenght; i++) { 
    //inner loop for all the elements in s1 
    for (int i = 0; i < s1.lenght; i++) { 
    matchFound = true; 
    System.out.println("This " + s2[i] + "was found"); 
    } 
} 
if(matchFound == false) { 
    System.out.println("This " + s2[i] + "was not found"); 
} 
//set matchFound bool back to false 
matchFound = false; 
} 

Answer 1

我用正確的答案更新了我的問題。

Answer 2

如果你的數組沒有重複的值，或者你只對沒有出現的元素感興趣，那麼你可以使用Set。

轉換陣列兩組：

Set<T> one = new HashSet<T>(Arrays.asList(s1));

Set<T> two = = new HashSet<T>(Arrays.asList(s2));

one.removeAll(secondSet);

two.removeAll(firstSet);

如果兩個集都是空的，那麼兩個集都是相等的，否則每個集都有唯一的元素。