Onchange Combobox事件不起作用

Question

顯示Jquery UI的JDatePicker時出現問題。 我想在Combobox中有onchange事件時顯示不同的格式。 這是我的代碼，當第二個onchange事件觸發時它不起作用。

Javascript代碼

$(document).ready(function() { 
    $("tr.golf_name").hide(); 
    $("tr.location").hide(); 

    $('input.type').click(function(event){ 
     var selectVal = $(this).val(); 

     if(selectVal == "tournament") { 
      $("tr.golf_name").show(); 
      $("tr.location").show(); 
     } else { 
      $("tr.golf_name").hide(); 
      $("tr.location").hide(); 
     } 
    }); 

    $('#price_type').change(function(){ 
     var selectedVal = $(this).val(); 
     if(selectedVal != "none") { 
      $('#golf_name').attr("disabled", false); 
      $('#location').attr("disabled", false); 

      $('#startdate').attr("disabled", false); 
      $('#enddate').attr("disabled", false); 
      $('#start_time1').attr("disabled", false); 
      $('#start_time2').attr("disabled", false); 
      $('#end_time1').attr("disabled", false); 
      $('#end_time2').attr("disabled", false); 
      $('#details').attr("disabled", false); 
      $('#submit').attr("disabled", false); 

      if($("option:selected",this).text() == "weekday") { 
       // Holiday List 
       var unavailableDates = ["9-3-2012", "14-3-2012", "15-3-2012"]; 
       // Exeptions if some Weekends are Working days 
       var enableDay = ["3-3-2012", "10-3-2012", "17-3-2012"]; 
       // Weekend Days Sunday = 0 ... Sat =6 
       var weekend = [0, 6]; 
       function nationalDays(date) { 
        // get date 
        dmy = date.getDate() + "-" + (date.getMonth() + 1) + "-" + date.getFullYear(); 


        // if Holiday then block it  
        if ($.inArray(dmy, unavailableDates) > -1) { 
         return [false, "", "Unavailable"]; 

        } 
        // if Exception then Enable it 
        if ($.inArray(dmy, enableDay) > -1) { 
         return [true, ""]; 

        } 

        //if Weekend then block it 
        if ($.inArray(date.getDay(), weekend) > -1) { 
         return [false, "", "Unavailable"]; 
        } 

        return [true, ""]; 
       } 

       $(function() { 
        $("#startdate").datepicker({ 
         dateFormat: 'dd MM yy', 
         beforeShowDay: nationalDays 
        }); 
       }); 
      } else { 
       var weekday = [1,2,3,4,5]; 
       function weekDays(date) { 
        // get date 
        dmy = date.getDate() + "-" + (date.getMonth() + 1) + "-" + date.getFullYear(); 

        //if Weekend then block it 
        if ($.inArray(date.getDay(), weekday) > -1) { 
         return [false, "", "Unavailable"]; 
        } 

        return [true, ""]; 
       } 

       $(function() { 
        $("#startdate").datepicker({ 
         dateFormat: 'dd MM yy', 
         beforeShowDay: weekDays 
        }); 
       }); 
      } 
     } else { 
      $('#golf_name').attr("disabled", true); 
      $('#location').attr("disabled", true); 

      $('#startdate').attr("disabled", true); 
      $('#startdate').attr("disabled", true); 
      $('#enddate').attr("disabled", true); 
      $('#start_time1').attr("disabled", true); 
      $('#start_time2').attr("disabled", true); 
      $('#end_time1').attr("disabled", true); 
      $('#end_time2').attr("disabled", true); 
      $('#details').attr("disabled", true); 
      $('#submit').attr("disabled", true); 
     } 
    }); 
}); 

這是我的HTML代碼。

<tr height=22> 
      <td align=right>Select Price</td> 
      <td>: 
       <select name="price_type" id="price_type"> 
        <option value="none">Select Price Type</option> 
        <option value="2">tournament</option> 
        <option value="3">weekday</option> 
       </select> 
      </td> 
     </tr> 
     <tr><td bgcolor=d9d9d9 width=800 height=1 colspan=2></td></tr> 

<tr height=22> 
      <td align=right>Start Date</td> 
      <td>: 
       <input type="text" name="startdate" id="startdate" disabled /> (yyyy/mm/dd) 
      </td> 
     </tr> 
     <tr><td bgcolor=d9d9d9 width=800 height=1 colspan=2></td></tr> 

您可以在此Fiddle

查看如何處理這個問題？謝謝。

Answer 1

您應該使用.prop()設置禁用狀態，而不是.attr()像

$('#startdate').prop("disabled", true); 

閱讀：prop vs attr

演示：Fiddle

Answer 2

我覺得這裏的問題VAR selectedVal = $（本） .VAL（）;因爲你的Combobox是父母，所以你需要得到它的selectedItem。