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PHP 7 我想列出，在下拉菜單按鈕是動態的帶動下，天多用途陣列中的下拉菜單返回星期只有一次一週，如果它們出現在查詢中。不過，我只想要一個結果每天打印，即使會有更多。PHP的 - 使用從DB查詢
例如：如果在星期一有12個客戶被分配，我只希望在我的下拉菜單中打印一個'星期一'結果。 This is an example of下拉按鈕應該如何在執行查詢中列出的日期。 #note該Customer表對於週三2項作爲Customers按鈕指示降了下來，但我只想週三在下拉爲Routes列出一次。
*基本上查詢被從表中*其中一個USER_ID =「SESSION_ID」，這個訂單通過一個天列，它是在DB數字形式;週一至週日1-7。
$sql = "
SELECT *
FROM `customers`
WHERE `users_id` = '1'
ORDER BY `cust_route_day` ASC
LIMIT 0 , 30";
$cust = new User;
$results = $cust->db->query($sql);
User來自連接到數據庫並執行各種查詢的用戶類。 定義和聲明。
$custName = array();
$custRouteDay = array();
$custID = array();
while ($row = $results->fetch_assoc())
{
$custName[] = $row['cust_first_name'].' '.$row['cust_last_name'];
$custRouteDay[] = $row['cust_route_day'];
$custID[] = $row['cust_id'];
}
define("CUSTID", $custID);
define("USER_TASKS", [
'Task Info' => 'Task Info',
'Task Time' => 'Task Time',
'Customer Route Info' => 'Customer Route Info',
'Set Alert' => 'Set Alert'
]);
define("CUSTOMERS", $custName);
define("USER_TASKS", $userTasks);
// Assign the abbr value of day ex: 'Wed' to numerical value from DB ex: '2'
foreach(CUST_ROUTE_DAY as $key => $value){
$newKey .= ROUTEDAY[$value]." ";
$custRouteKeyArray = explode(" ",$newKey);
}
define("NAVICONS", [
"glyphicon glyphicon-user",
"glyphicon glyphicon-road",
"glyphicon glyphicon-tasks",
"fa fa-sitemap",
"fa fa-globe"
]);
define("STYLE", [
"fixed-bottom" => "navbar navbar-default navbar-fixed-bottom",
"fixed-top" => "navbar navbar-default navbar-fixed-top",
"default" => "navbar navbar-default"
]);
define("NAVBTNS", [
"Customers"=>CUSTOMERS,
"Route Info"=>$custRouteKeyArray,
"Tasks"=>USER_TASKS,
"Networking",
"Maps"
]);
定義的陣列NAVBTNS：
Array ([0] => John Banner [1] => Dale Landry [2] => Bill Childers [3] => Darren Little [4] => Gary Garland) Array ([0] => Mon [1] => Wed [2] => Wed [3] => Thur [4] => Fri [5] =>) Array ([Task Info] => Task Info [Task Time] => Task Time [Customer Route Info] => Customer Route Info [Set Alert] => Set Alert) NetworkingMaps
創建導航菜單btns和下拉BTN功能。基本上，如果數組由子數組組成，請創建一個下拉按鈕並適當地分配鍵和值。
function construct_navbar_buttons(){
//because key values in the parent array are mixed numerical and char values
//define and increment $i each time through the loop for NAVICONS class values and page number key
$i = 0;
//Start the post variable that will hold the result string $btns <ul>
$btns = '<ul class="nav navbar-nav">';
foreach(NAVBTNS as $k => $v){//$k holds index or e.g. Customers
if(is_array($v)){//go over subarray else print button see //we have a string value
$filtered = array_filter($v);//array_filter to remove null values
if(empty($filtered)) {
$btns .= '<li><a href="?p='.$v.'"><i class="'.NAVICONS[$i].'"></i> '.$v.'</a></li>';
}else{//start drop down here
$btns .= '<li class="dropdown">
<a class="dropdown-toggle" data-toggle="dropdown" href="">
<i class="'.NAVICONS[$i].'"></i> '.$k.' <span class="caret"> </span>
</a>
<ul class="dropdown-menu dropdown-user">';
foreach($v as $key => $value){//loop through results of child array
if(in_array($v[$key], $v)){ //locate instance where key exists and print list-item a tag button in drop-down
################################################################
## need logic to go over first instance of a value within the ##
## parent array to print only that first value in the results ##
################################################################
$btns .= '<li><a href="?p='.$k.'&n='.$v[$key].'">'.$v[$key].'</a></li>';
}
}
$btns .= "</ul>\n</li>";//close the parent UL and LI tags
}
}else{//we have a string value
//do stuff example data: Tasks - key here seems aways a index number
$btns .= '<li><a href="?p='.$v.'"><i class="'.NAVICONS[$i].'"></i> '.$v.'</a></li>';
}
$i++;print_r($v);
}
$btns .= '</ul>';
return $btns;
}
使用array_search試過，但是這不是給我，我希望
$d = array_search($value, $v);
if($d = ROUTEDAY[$i]){
echo $value;
}
$day = array("Mon","Tue","Wed","Thur","Fri","Sat","Sun");
if($d = $day[$i]){
echo $day[$i];
}
ROUTEDAY的結果被定義的變量保存與鍵的值一週的日子裏，給了我下面的結果在一個簡單的回聲。 1 - MonWedWedThurFriTask InfoTask TimeCustomer Route InfoSet Alert 2 - MonTueWed 我以爲array_search只給了您在數組中第一次出現的值。
我已經嘗試爲數組的每個實例創建單獨的foreach循環，但這使事情變得複雜，我希望僅使用兩個foreach循環完成此操作。我非常接近這一點。如果有人能幫助，我會非常感激。