Tkinter登錄和菜單程序

Question

我正在製作一個Tkinter Python progarm，它將有一個登錄頁面，登錄後將顯示一個供用戶進行交互的菜單頁面。

我的代碼，其中包括測驗類，起始頁類，菜單類，難度類和登錄頁面如下：

import tkinter as tk 
from tkinter import * 
import tkinter.messagebox as tm 
class Quiz (tk.Tk): 
    def __init__ (self, *args , **kwargs): 
     tk.Tk.__init__(self, *args , ** kwargs) 
     container = tk.Frame (self) 
     container.pack (side = "top" , fill = "both" , expand = True) 
     container.grid_rowconfigure (0,weight = 1) 
     container.grid_columnconfigure (0,weight = 1) 
     self.frames = {} 
     for F in (StartPage, Menu, Difficulty): 
      frame = F(container, self) 
      self.frames[F] = frame 
      frame.grid (row = 0, column = 0 , sticky = "nsew") 
     self.show_frame(StartPage) 
    def show_frame(self,cont): 
     frame = self.frames[cont] 
     frame.tkraise() 

class StartPage(tk.Frame): 
    def __init__(self, parent, controller): 
     tk.Frame.__init__(self,parent) 
     label = tk.Label(self, text = "Login") 
     label.pack(pady = 10 , padx = 10) 
     Username = tk.Entry(self) 
     Username.pack() 
     Password = tk.Entry (self, show = "*") 
     Password.pack() 
     button1 = tk.Button(self, text = "Login", command = lambda: Login(Username,Password,parent,controller,self)) 
     button1.pack() 

class Menu(tk.Frame): 
    def __init__ (self, parent, controller) : 
     tk.Frame.__init__(self, parent) 
     label = tk.Label(self, text = "Menu") 
     button1 = tk.Button(self, text = "Histoy", command = lambda: controller.show_frame(Difficulty)) 
     button1.pack() 
     button2 = tk.Button(self, text = "Maths", command = lambda: controller.show_frame(Difficulty)) 
     button2.pack() 
     button3 = tk.Button(self, text = "Music", 
         command = lambda: controller.show_frame(Difficulty)) 
     button3.pack() 

class Difficulty(tk.Frame): 
    def __init__ (self, parent, controller): 
     tk.Frame.__init__(self,parent) 
     label = tk.Label(self, text = "Difficulty") 
     Easy = tk.Button(self, text = "Easy", command = lambda: controller.show_frame(Difficulty)) 
     Easy.pack() 
     Medium = tk.Button(self, text = "Medium",command = lambda: controller.show_frame(Difficulty)) 
     Medium.pack() 
     Hard = tk.Button(self, text = "Hard", command = lambda: controller.show_frame(Difficulty)) 
     Hard.pack() 
     backtomenu = tk.Button(self, text = "Back to Menu", command = lambda: controller.show_frame(Menu)) 
     backtomenu.pack() 

def Login(Username,Password,parent,controller,self): 
    Usernames = [] 
    count = 0 
    Username = Username.get() 
    Password = Password.get() 
    try: 
     with open ("Usernames&Passwords.txt" , "r", encoding = "UTF-8") as     file: 
      for each in file: 
       Usernames.append(each.strip("\n")) 

except IOError as error: 
    print (error) 
    if Usernames[count] == Username : 
     if Usernames[count + 1] == Password: 
      Menu(parent, controller) 
      print ("Hi") 
     else: 
      tm.showinfo("Username or Password is Incorrect") 

    else: 
      tm.showinfo("Username or Password is Incorrect") 
app = Quiz() 
app.geometry ("500x300") 
app.mainloop() 

當我運行的代碼沒有顯示錯誤消息，但它不會運行Menu類，因此它不會轉到下一個Tkinter框架以繼續使用該程序。有人能幫助我指出爲什麼Main類沒有運行的正確方向。提前致謝。

Answer 1

您必須在顯示下一個之前銷燬所有其他小部件。 在菜單（父級，控制器）之前插入self.destroy()。 同樣的事情必須由困難來完成。

編輯：As @Bryan Oakley指出，這是錯誤的解決方案。改爲Menu(parent, controller)爲controller.show_frame(Menu)