cypher如何從其他節點的子串創建獨特節點

Question

我是Cypher和Neo4j的新手。我有一組標有「線」每一行是一個很長的字符串，如節點： 0067011990999991950051507004+68750+023550FM-12+038299999V0203301N00671220001CN9999999N9+00001+99999999999

有跡象表明我關心大約兩子：year和temp

match(l:Line) 
return toInteger(substring(l.line,15,4)) as year, toInteger(substring(l.line,87,5)) as temp 
limit (5) 

爲了給：

year temp 

1941 44 

1942 90 

1942 12 

1948 100 

1948 -21 

我需要創建一套標有「年」爲今年的每個唯一值的節點，一組不一的標有「溫度」爲每一個獨特的溫度讀數。我還需要使用關係has_temp將每年的溫度讀數關聯起來。 。（然後打印一年，溫度讀數和關係型降序排序的年度順序

任何幫助，將不勝感激

Answer 1

試試這個：

match(l:Line) 
with toInteger(substring(l.line,15,4)) as year, 
toInteger(substring(l.line,87,5)) as temp 
MERGE (y:Year{value:year}) 
MERGE (t:Temp{value:temp}) 
MERGE (y)-[s:has_temp]->(t) 
RETURN year,temp,type(s) as rel_type order by year desc 

如果你想檢查後如何導入的節點，你可以這樣做：！？

MATCH (y:Year)-[r]->(t:Temp) 
RETURN y.value as year,t.value as temp,type(r) as re_tzpe order by year desc