如何在字符串中查找@ [XX：XXXX]的所有實例，然後查找周圍的文本？

Question

給予相同的字符串：

"@[19:Sara Mas] what's the latest with the TPS report? @[30:Larry Peters] can you help out here?" 

我想找到一種方法來動態返回，標記用戶和圍繞內容。結果應該是：

user_id: 19 
copy: what's the latest with the TPS report? 

user_id: 30 
copy: can you help out here? 

任何有關如何使用ruby/rails完成的想法？謝謝

這個正則表達式如何找到匹配？

@\[\d+:\w+\s\w+\] 

Answer 1

result = subject.scan(/\[(\d+).*?\](.*?)(?=@|\Z)/m) 

這分別在反向引用1和2中獲取id和內容。要停止捕獲，必須滿足@或字符串的結尾。

" 
\\[   # Match the character 「[」 literally 
(   # Match the regular expression below and capture its match into backreference number 1 
    \\d   # Match a single digit 0..9 
     +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
) 
.   # Match any single character that is not a line break character 
    *?   # Between zero and unlimited times, as few times as possible, expanding as needed (lazy) 
\\]   # Match the character 「]」 literally 
(   # Match the regular expression below and capture its match into backreference number 2 
    .   # Match any single character that is not a line break character 
     *?   # Between zero and unlimited times, as few times as possible, expanding as needed (lazy) 
) 
(?=  # Assert that the regex below can be matched, starting at this position (positive lookahead) 
       # Match either the regular expression below (attempting the next alternative only if this one fails) 
     \@   # Match the character 「\@」 literally 
    |   # Or match regular expression number 2 below (the entire group fails if this one fails to match) 
     \$   # Assert position at the end of the string (or before the line break at the end of the string, if any) 
) 
" 

這將匹配從@開始並結束於標點符號的內容。對不起，如果我不正確理解。

result = subject.scan(/@.*?[.?!]/) 

Answer 2

拆分字符串，然後迭代處理內容。我認爲這不會超過：

tmp = string.split('@').map {|str| [str[/\[(\d*).*/,1], str[/\](.*^)/,1]] } 
tmp.first #=> ["19", "what's the latest with the TPS report?"] 

這有幫助嗎？