多ID檢查WHERE條件

Question

我有一個查詢，我需要得到只有在WHERE子句

下面是該查詢

SELECT CompanyId 
FROM vendors 
WHERE VendorId 
IN (
'306145244', '1011073437' 
) 

的所有ID匹配我希望有一個行的所有CompanyId其中有vendorId'306145244'和'1011073437'

如果其中一個VendorId匹配，我不想那companyId。雙方應VENDORID分組時我需要2行類似下面

company Id Vendor Id 
1    306145244 
1    1011073437 
2    306145244 
2    306145244 

如果可能，我希望在這ORACLE查詢匹配

。

Answer 1

你可能需要看看ALL。

SELECT CompanyId 
FROM vendors 
WHERE VendorId = ALL (
    query to get numbers. 
) 

http://dev.mysql.com/doc/refman/5.5/en/all-subqueries.html

Answer 2

SELECT CompanyId 
FROM vendors 
WHERE VendorId IN ('306145244', '1011073437') 
GROUP BY CompanyId 
HAVING COUNT(*) = 2 

• SQLFiddle Demo

OTHER LINK：

• SQL of Relational Division

---

如果vendorID不是每個CompanyId獨特，一DISTINCT關鍵字是需要計數唯一的值，

SELECT CompanyId 
FROM vendors 
WHERE VendorId IN ('306145244', '1011073437') 
GROUP BY CompanyId 
HAVING COUNT(DISTINCT VendorId) = 2 

Answer 3

SELECT `CompanyId` , count(`CompanyId`) 
FROM `vendors` 
WHERE VendorId 
IN (
'306145244', '1011073437' 
) 
GROUP BY `CompanyId` 
HAVING count(`CompanyId`) = 2; 

用這個，這是爲我工作和測試。

Answer 4

在SQL Server我們可以做的是：

SELECT CompanyId 
FROM vendors 
WHERE VendorId 
IN ('306145244') 
intersect 
SELECT CompanyId 
FROM vendors 
WHERE VendorId 
IN ('1011073437') 

但MYSQL不支持intersect。因此，我們必須接近alternative to intersect in MYSQL

select distinct CompanyId 
FROM vendors 
where vendorId IN ('306145244') 
and CompanyId IN 
(SELECT CompanyId 
FROM vendors 
WHERE VendorId 
IN ('1011073437')) 

編輯

select CompanyId,VendorId 
FROM vendors 
where vendorId IN ('306145244') 
and CompanyId IN 
(SELECT CompanyId 
FROM vendors 
WHERE VendorId 
IN ('1011073437')) 
union 
select CompanyId,VendorId 
FROM vendors 
where vendorId IN ('1011073437') 
and CompanyId IN 
(SELECT CompanyId 
FROM vendors 
WHERE VendorId 
IN ('306145244')) 

SQL Fiddle

Answer 5

試試這個：

SELECT CompanyId,VendorId 
FROM vendors 
WHERE VendorId 
IN (
select VendorId from vendors 
) 
order by CompanyId asc; 

希望它能幫助你。