如何從「int a，b，c = 0，d;」子字符串（變量名稱）

我有我的代碼從它的文本文件和子（變量名）來搜索字符串「INT」，但我對串（變量名）如何從「int a，b，c = 0，d;」子字符串（變量名稱）

像一些問題「INT A，B， c = 0，d;「

我想我的輸出是：

變量名是：一個
變量名是：乙
變量名是：c
變量名：d

我可以修改我的代碼嗎？

這是我的代碼。

   //print variable name and position 
       int k4 = line.indexOf("=",k+1); 
       int k5 = line.indexOf(";", k+1); 
       int k6 = line.indexOf(",", k+1); 
       int cTemp1 = 0; 

       //Count whitespace before variable name, print variable name and length of variable name 
       if (k4 != -1){ 
        String temp4 = line.substring(k+3, k4);  //Substring variable name 
        if(k4 != -1){ 
         int varName = line.indexOf(temp4.trim(), k+3); 
         String total_length = line.substring(k+3, varName);  
         int wPattern = total_length.length();  
         System.out.println(" - Whitespace before variable name \"" + temp4.trim() + "\" are: ," + wPattern); 
        } 
        System.out.println(" - Variable name type INTEGER at line: " + lineNumber + " is: "+temp4.trim()); 
        System.out.print(" - Length of variable name \"" + temp4.trim() + "\" is: ," + temp4.trim().length() + "\n\n"); 
        varLength_Integer1 += temp4.trim().length(); 
       } 
       else if(k5 != -1){ 
        String temp5 = line.substring(k+4, k5); 
        System.out.println(" - Variable name type INTEGER at line: " + lineNumber + " is: "+temp5.trim()); 
        System.out.print(" - Length of variable name \"" + temp5.trim() + "\" is: ," + temp5.trim().length() + "\n\n"); 
        varLength_Integer2 += temp5.trim().length(); 
       } 
       else if(k6 != -1){ 
        String temp6 = line.substring(k+4, k6); 
        System.out.println(" - Variable name type INTEGER at line: " + lineNumber + " is: "+temp6.trim()); 
        System.out.print(" - Length of variable name \"" + temp6.trim() + "\" is: ," + temp6.trim().length() + "\n\n"); 
        varLength_Integer3 += temp6.trim().length(); 
       } 
       avgInteger += (varLength_Integer1 + varLength_Integer2 + varLength_Integer3)/(double)c3; 
       //END Count whitespace before variable name, print variable name and length of variable name 

      }

非常感謝。

來源

2016-03-01 Anonymous

我想與正則表達式這樣

import java.util.regex.Matcher; 
import java.util.regex.Pattern; 

public class ParseInt { 

    public static void main(String[] args) { 
     String test = "int a, b, c = 0, d;\n\nint e, b, c = 0, d"; 

     String pattern = "int(.*)"; 
     Pattern r = Pattern.compile(pattern); 

     String patternVar = "([A-Za-z][a-zA-Z_0-9]*)(\\[\\])?"; 
     Pattern rVar = Pattern.compile(patternVar); 

     String[] linesNewline = test.split("\n"); 

     for (int nLI=0;nLI < linesNewline.length; ++nLI) { 
      String[] lines = linesNewline[nLI].split(";"); 
      for (int i=0;i < lines.length; ++i) { 
       Matcher m = r.matcher(lines[i]); 
       if (m.find()) { 
        String[] variables = m.group(1).split(","); 
        for (int ii=0; ii < variables.length; ++ii) { 
         Matcher mVar = rVar.matcher(variables[ii].trim()); 
         if (mVar.find()) { 
          System.out.println("Variable is " + mVar.group(1)); 
        } 
       } 
      } 
     } 
    } 
    } 
}

的輸出是輸入字符串「INT A，B，C = 0，d; \ n \ NINT E，B，C = 0， d「

Variable is a 
Variable is b 
Variable is c 
Variable is d 
Variable is e 
Variable is b 
Variable is c 
Variable is d

輸出用於輸入字符串」int a，a1，b，b1;「

Variable is a 
Variable is a1 
Variable is b 
Variable is b1

的輸出是輸入字符串爲「int d [] = {31，28，31，30，31，30，31，31，30，31，30，31};」

Variable is d

的輸出是輸入字符串「INT D0 = sc.nextInt（）; INT D1 = sc.nextInt（）; INT D2 = sc.nextInt（）;」

Variable is d0 
Variable is d1 
Variable is d2

來源

2016-03-01 10:51:41 Kordi

是的，它的工作，但如果「int a，a1，b，b1;」我會在「String patternVar =」（[A-Za-z _] *）中加上0-9「;」對嗎？並且如果像這樣輸入「int d [] = {31,28,31,30,31,30,31,31,30,31,30,31};」出放是 - 變量是28 - 變量是31 - 變量是30 - 變量是31 - 變量是30 - 變量是31 - 變量是31 - 變量是30 - 變量是31 - 變量爲30 - 變量爲31 但是，我只想要「d」。我該如何修改你的代碼？非常感謝。 – Anonymous

@匿名等待只是在幾分鐘內更新我的代碼，它通常應該是patternVar =（[A-Za-z _] *）（[]）？「但測試它 – Kordi

@匿名確定更新我的代碼，到 – Kordi

你可以試試 -

String inputTxt = "int aa, b, c = 0, d=89;"; 
inputTxt = inputTxt .replaceAll("int ", "") 
        .replaceAll(";", ",") 
        .replaceAll("=.\\d,", ","); 
String[] varNames = inputTxt.split(","); 

for (String var : varNames) { 
    System.out.println(var); 
}

您可以更改代碼，按您的要求。但這會給你一個更好的起點。

來源

2016-03-01 10:47:48 Kartic

如何從「int a，b，c = 0，d;」子字符串（變量名稱）

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