變化eregi用的preg_match

Question

可能重複：
How can I convert ereg expressions to preg in PHP?

這是我處理的代碼：

foreach($domainextensions as $extension => $who) {      
    $buffer = NULL;  
    if ($sock = fsockopen($who[0], 43) or die('sock' . $sock)); 
    fputs($sock, $domain.$extension . "\r\n"); 

    while(!feof($sock)) { 
     $buffer .= fgets($sock,128); 
    } 

    fclose($sock); 

    if(preg_match($who[1],$buffer)) { 
     echo ''; 
    } 

的錯誤是：

Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash in somewhere.php 
if(preg_match($who[1],$buffer)){} 

原始功能是eregi和eregi正常工作，但eregi已經deperecated：

if(eregi($who[1],$buffer)){} 

如何改變preg_match定義定義分隔符？

Answer 1

foreach($domainextensions as $extension => $who) {      
        $buffer = NULL;  
        if ($sock = fsockopen($who[0], 43) 
        /
        or die('sock' . $sock)); 
        fputs($sock, $domain.$extension . "\r\n"); 

          while(!feof($sock)) 
          { 
            $buffer .= fgets($sock,128); 
          } 

        fclose($sock); 

        if(preg_match('/'.$who[1].'/i',$buffer)) 
        { 
          echo ''; 
        } 

應該定界符提前:)你是最好的和快速的模式